operator重载之矩阵的运算—C++

/*
功能：矩阵的运算
作者：wind
日期：2013-11-29
*/
#include <iostream>
#include <string>
using namespace std;
/************************************************************/
class Reckle
{
public:
	Reckle()
	{
		m_iA = 0;
		m_iB = 0;
		m_iC = 0;
		m_iD = 0;
	}
	void set(double aA,double aB,double aC,double aD);
	void get()const;
	Reckle operator + (Reckle c1);
	Reckle operator - (Reckle c1);
	void display(Reckle c1);
private:
	double m_iA;
	double m_iB;
	double m_iC;
	double m_iD;
};
/************************************************************/
void Reckle::set(double aA,double aB,double aC,double aD)
{
	m_iA = aA;
	m_iB = aB;
	m_iC = aC;
	m_iD = aD;
}
void Reckle::get()const
{
	cout<<"The result is:"<<endl;
	cout<<"("<<m_iA<<","<<m_iB<<")"<<endl;
	cout<<"("<<m_iC<<","<<m_iD<<")"<<endl;
}
Reckle Reckle::operator + (Reckle c1)
{
    Reckle c;
	c.m_iA = m_iA + c1.m_iA;
	c.m_iB = m_iB + c1.m_iB;
	c.m_iC = m_iC + c1.m_iC;
	c.m_iD = m_iD + c1.m_iD;
	return c;
}
Reckle Reckle::operator - (Reckle c1)
{
	Reckle c;
	c.m_iA = m_iA - c1.m_iA;
	c.m_iB = m_iB - c1.m_iB;
	c.m_iC = m_iC - c1.m_iC;
	c.m_iD = m_iD - c1.m_iD;
	return c;
}

void Reckle::display(Reckle c1)
{
	string n;
	Reckle c;
	cout<<"Please input the sign(-/+):";
	cin>>n;
	if  ("-" == n)
	{
		c = operator- (c1);
		cout<<"The result is:"<<endl;
		cout<<"("<<c.m_iA<<","<<c.m_iB<<")"<<endl;
		cout<<"("<<c.m_iC<<","<<c.m_iD<<")"<<endl;
	}
	else if ("+" == n)
	{
		c = operator+ (c1);
		cout<<"The result is:"<<endl;
		cout<<"("<<c.m_iA<<","<<c.m_iB<<")"<<endl;
		cout<<"("<<c.m_iC<<","<<c.m_iD<<")"<<endl;
	}
	else
	{
		cout<<"The operator is error";
	}
}
/************************************************************/
int main(void)
{

	Reckle c1,c2;
	double x = 0;
	double y = 0;
	double z = 0;
	double h = 0;

	cout<<"请输入第一个矩阵(两行两列)："<<endl;
	cin>>x>>y>>z>>h;
	c1.set(x,y,z,h);

	cout<<"请输入第二个矩阵(两行两列)："<<endl;
	cin>>x>>y>>z>>h;
	c2.set(x,y,z,h);

    c1.display(c2);
	system("pause");
	return 0;
}