Pandas-23.时间差

print(pd.Timedelta('2 days 2 hours 15 minutes 30 seconds'))
'''
2 days 02:15:30
'''

print(pd.Timedelta(6, unit='h'))
'''
0 days 06:00:00
'''

print(pd.Timedelta(hours=2))
'''
0 days 02:00:00
'''

s = pd.Series(pd.date_range('2012-1-1', periods=3, freq='D'))
td = pd.Series([ pd.Timedelta(days=i) for i in range(3) ])
df = pd.DataFrame(dict(A = s, B = td))
print(df)
'''
           A      B
0 2012-01-01 0 days
1 2012-01-02 1 days
2 2012-01-03 2 days
'''

print(df['A'] + df['B'])
'''
0   2012-01-01
1   2012-01-03
2   2012-01-05
dtype: datetime64[ns]
'''

print(df['A'] - df['B'])
'''
0   2012-01-01
1   2012-01-01
2   2012-01-01
dtype: datetime64[ns]
'''