pay_time
选取的是 timestamp
类型;
此时需要进行时间段的数据分组剥离,在此做一下实现方式,请多指教 …
框架:ThinkPHP5.1.2
系统:nginx/win10 、phpStudy2017
group
分组技巧;pay_time
中记录的字段数据进行 24时
的定位切分;
这里可以用到 substring()
方法的支持 【字段取值举例:2019-08-23 09:25:09
】ThinkPHP5
框架的代码规范$res = Db::name('order_goods og')
->field("substring(pay_time,12,2) hour,count(og.id) count")
->join("order_infos oi","oi.order_id = og.order_id")
->where([ ["pay_status","=",1]])
->group('hour')
->order('hour','asc')
->select();
SELECT substring(pay_time,12,2) hour,count(og.id) count FROM tp5_xorder_goods og
INNER JOIN `tp5_xorder_infos` `oi` ON `oi`.`order_id`=`og`.`order_id`
WHERE `pay_status` = 1
GROUP BY `hour`
ORDER BY `hour` ASC
ECharts图表库
进行数据展示为例,那么我的处理方式如下:$timeRes = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0];
foreach ($timeRes as $key => $value){
foreach ($res as $key2 => $value2){
$hour = intval($value2['hour']);
if ($key == $hour){
$timeRes[$key] = $value2['count'];
//echo "hour:".$hour.";key:".$key.";count:".$value2['count']."<br/>";
break;
}else{
continue;
}
}
}
MySQL substring()函数
- mysql 获取某个时间段每一天的统计数据