前往小程序,Get更优阅读体验!
立即前往
首页
学习
活动
专区
工具
TVP
发布
社区首页 >专栏 >数据结构学习-python实现-二叉搜索树--0415

数据结构学习-python实现-二叉搜索树--0415

原创
作者头像
到不了的都叫做远方
修改2020-04-15 20:00:09
4630
修改2020-04-15 20:00:09
举报
文章被收录于专栏:翻译scikit-learn Cookbook

二叉查找树的生成,以及增删查,删除最为复杂,考虑的情况特别多,左右子树,容易把人弄乱。最重要的是删除后,需要将其右子树的最小值补充过来,有一番替换的过程。

代码语言:python
代码运行次数:0
复制
class BinarySearchTree:
    def __init__(self):
        self.root = None
        self.size = 0

    def length(self):
        return self.size

    def __len__(self):
        return self.size

    def __iter__(self):
        return self.root.__iter__()

    def put(self, key, val):  # 插入操作
        if self.root:  # 若已存在根节点,直接插入数据
            self._put(key, val, self.root)
        else:  # 不存在根节点,则插入根节点的值
            self.root = TreeNode(key, val)
        self.size += 1

    def _put(self, key, val, currentnode):
        if key < currentnode.key:  # 若插入值与根节点的值的大小,将插入值链接到左或右子节点
            if currentnode.hasleftchild(): 
                self._put(key, val, currentnode.leftchild)
            else:
                currentnode.leftchild = TreeNode(key, val, parent=currentnode)
        else:
            if currentnode.hasrightchild():
                self._put(key, val, currentnode.rightchild)
            else:
                currentnode.rightchild = TreeNode(key, val, parent=currentnode)

    def __setitem__(self, key, value):
        self.put(key, value)

    def get(self, key):  # 查找方法
        if self.root:
            res = self._get(key, self.root)
            if res:
                return res.payload
            else:
                return None
        else:
            return None

    def _get(self, key, currentnode):  # 查找节点
        if not currentnode:
            return None
        elif currentnode.key == key:
            return currentnode
        elif key < currentnode.key:
            return self._get(key, currentnode.leftchild)  # 递归的查找
        else:
            return self._get(key, currentnode.rightchild)

    def __getitem__(self, key):
        return self.get(key)

    def __contains__(self, key):
        if self._get(key, self.root):
            return True
        else:
            return False

    def delete(self, key):  # 删除节点
        if self.size > 1:
            nodetoremove = self._get(key, self.root)  # 先查找要删除的节点
            print(nodetoremove.payload)
            if nodetoremove:
                self.remove(nodetoremove.key,nodetoremove)  # 找到了就调用remove方法
                self.size -= 1
            else:
                raise KeyError('Error, key not in tree')
        elif self.size == 1 and self.root.key == key:
            self.root = None
            self.size -= 1
        else:
            raise KeyError('Error, key not in tree')

    def remove(self, key, currentnode):
        if currentnode.isleaf():  # 删除节点为叶节点,则将父节点的相应子节点设置为None
            if currentnode == currentnode.parent.leftchild:
                currentnode.parent.leftchild = None
            else:
                currentnode.parent.rightchild = None
        elif currentnode.hasbothchildren():  # 若有两个子节点,则寻找右子节点的最小节点,替换该位置
            succ = currentnode.findsuccessor()
            succ.spliceout()
            currentnode.key = succ.key
            currentnode.payload = succ.payload
        else:
            if currentnode.hasleftchild():
                if currentnode.isleftchild():
                    currentnode.leftchild.parent = currentnode.parent
                    currentnode.parent.leftchild = currentnode.leftchild
                elif currentnode.isrightchild():
                    currentnode.leftchild.parent = currentnode.parent
                    currentnode.parent.rightchild = currentnode.leftchild
                else:
                    currentnode.replacenodedata(currentnode.leftchild.key,currentnode.leftchild.payload,currentnode.leftchild.leftchild,currentnode.leftchild.rightchild)
            else:
                if currentnode.isleftchild():
                    currentnode.rightchild.parent = currentnode.parent
                    currentnode.parent.leftchild = currentnode.rightchild
                elif currentnode.isrightchild():
                    currentnode.rightchild.parent = currentnode.parent
                    currentnode.parent.rightchild = currentnode.rightchild
                else:
                    currentnode.replacenodedata(currentnode.rightchild.key,currentnode.rightchild.payload,currentnode.rightchild.leftchild,currentnode.rightchild.rightchild)

    def __delitem__(self, key):
        self.delete(key)


class TreeNode:
    def __init__(self, key, val, left=None, right=None, parent=None):
        self.key = key
        self.payload = val
        self.leftchild = left
        self.rightchild = right
        self.parent = parent

    def hasleftchild(self):
        return self.leftchild

    def hasrightchild(self):
        return self.rightchild

    def isleftchild(self):
        return self.parent and self.parent.leftchild == self

    def isrightchild(self):
        return  self.parent and self.parent.rightchild == self

    def isroot(self):
        return not self.parent

    def isleaf(self):
        return not (self.rightchild or self.leftchild)

    def hasanychildren(self):
        return self.rightchild or self.leftchild

    def hasbothchildren(self):
        return self.rightchild and self.leftchild

    def replace_node_data(self, key, value, lc, rc):
        self.key = key
        self.payload = value
        self.leftchild = lc
        self.rightchild = rc
        if self.hasleftchild():
            self.leftchild.parent = self
        if self.hasrightchild():
            self.rightchild.parent = self

    def findsuccessor(self):
        succ = None
        if self.hasrightchild():
            succ = self.rightchild.findmin()
        return succ

    def findmin(self):
        current = self
        while current.hasleftchild():
            current = current.leftchild
        return current

    def spliceout(self):
        if self.isleaf():
            if self.isleftchild():
                self.parent.leftchild = None
            else:
                self.parent.rightchild = None
        elif self.hasanychildren():
            if self.isleftchild():
                self.parent.leftchild = self.leftchild  # 它应该没有左子树了,因为是最小值
            else:
                self.parent.rightchild = self.leftchild  # 应该不会出现
            self.leftchild.parent = self.parent  # 大体不会出现
        else:
            if self.isleftchild():
                self.parent.leftchild = self.rightchild  # 将被移走的节点的子树接到起父节点的相应子树上
            else:
                self.parent.rightchild = self.rightchild
            self.rightchild.parent = self.parent

    # def __iter__(self):  # 这个迭代代码始终报错,但是没有迭代的话,就不能for循环内部节点。还没解决这个问题
    #     if self:
    #        if self.hasleftchild():
    #            for elem in self.leftchild:
    #                yield elem
    #         yield self.key
    #         if self.hasrightchild():
    #             for elem in self.rightchild:
    #                 yield elem

if __name__ == "__main__":
    alist = [70, 31, 93, 94, 14, 23, 73]
    bst = BinarySearchTree()
    bst.put(alist[0], 'luffy')
    bst.put(alist[1], 'ace')
    bst.put(alist[2], 'sanji')
    bst.put(alist[3], 'joba')
    bst.put(alist[4], 'flank')
    bst.put(alist[5], 'solo')
    bst.put(alist[6], 'namei')
    print(len(bst))
    # bst.delete(alist[6])
    bst.delete(alist[0])
    # print(bst.root.leftchild.leftchild.rightchild.key)
    print(bst.root.key)

原创声明:本文系作者授权腾讯云开发者社区发表,未经许可,不得转载。

如有侵权,请联系 cloudcommunity@tencent.com 删除。

原创声明:本文系作者授权腾讯云开发者社区发表,未经许可,不得转载。

如有侵权,请联系 cloudcommunity@tencent.com 删除。

评论
登录后参与评论
0 条评论
热度
最新
推荐阅读
领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档