给定一棵二叉树,想象自己站在它的右侧,按照从顶部到底部的顺序,返回从右侧所能看到的节点值。
示例:
输入: [1,2,3,null,5,null,4]
输出: [1, 3, 4]
解释:
1 <---
/ \
2 3 <---
\ \
5 4 <---
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/binary-tree-right-side-view 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
class Solution {
public:
vector<int> rightSideView(TreeNode* root) {
vector<int> ans;
dfs(root, ans, 0);
return ans;
}
void dfs(TreeNode* root, vector<int> &ans, int level)
{
if(root == NULL)
return;
if(ans.size() == level)
ans.push_back(root->val);
dfs(root->right, ans, level+1);
dfs(root->left, ans, level+1);
}
};
class Solution {
public:
vector<int> rightSideView(TreeNode* root) {
if(root == NULL)
return {};
vector<int> ans;
queue<TreeNode*> q;
q.push(root);
int n;
while(!q.empty())
{
n = q.size();
ans.push_back(q.front()->val);
while(n--)
{
if(q.front()->right)
q.push(q.front()->right);
if(q.front()->left)
q.push(q.front()->left);
q.pop();
}
}
return ans;
}
};