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社区首页 >专栏 >shellcode 开发

shellcode 开发

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CN_Simo
发布2021-05-10 11:16:27
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发布2021-05-10 11:16:27
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文章被收录于专栏:Script Boy (CN-SIMO)

0x00 设置堆栈

栈顶指针按位与之后,将栈桢以16字节的大小对齐:

代码语言:javascript
复制
push rbp                    ;store rbp original state
mov rbp, rsp                ;set stack base point to current stack top
sub rsp, 60h                ;reserve stack space for called functions
and rsp, 0fffffffffffffff0h ;make sure stack 16-byte aligned

或者

代码语言:javascript
复制
push	rsi				; Preserve RSI since we're stomping on it
mov		rsi, rsp		; Save the value of RSP so it can be restored
and		rsp, 0FFFFFFFFFFFFFFF0h	; Align RSP to 16 bytes
sub		rsp, 020h		; Allocate homing space for ExecutePayload

我对内存对齐的理解:

把栈想象成一个积木堆成的楼,32位里每个积木能容纳4字节(32位),楼层高2的32次方,比如现在你在13楼里操作,发现13楼里堆了一部分东西,但是没有满,此时你有两种选择:继续在这楼里堆你的东西、再往上走几层重新开始堆。 第一种:继续在这楼里堆你的东西,当你堆的东西这层撑不下会移到下一层继续堆,此时让你找到最开始堆的东西的位置时候,你就要大费周章了,因为你要说在13楼哪个位置(具体到那个bit上),这就很影响寻址效率 如果是往上走走,从一个空楼层开始的地方堆的话,比如到了16楼,这时候不管你堆多少你都可以很方便的走到16楼,这就是第二种 现在16楼开始的地方就是你的东西,虽然牺牲了中间14楼15楼的空间,但是提高了效率,这就是内存里的空间换时间 对齐的方式有很多,上面说的就是以一层楼(4字节,32位)为对齐方式 很明显,如果13层楼只占用了1个字节(8位),那么你的东西至少会放在14楼开始的地方,但是你的东西只有2字节(16位),13楼足以容纳,却跑到了14楼,此时空间牺牲的就有点大了 就要适当缩小对齐单位,从4字节(32位)缩到2字节(16位),这时候你的东西就可以放在13楼里了,而且找到你的东西起始位置也很简单,从13楼开始的地方每隔2字节(16位)看一下,发现第二个2字节就是自己开始存东西的地方,很方便快速 对应到x64里也很简单,一层楼的大小变成了8字节(64位),楼高2的64次方,esp就是指向的当前楼层,按16个字节对齐的话,就是按两层楼对齐,两层楼里尽管只要有一点点东西,你的东西也要从后面两层重新堆 其实楼高多少,要和栈指针寄存器的容量相关

0x01 获取kernel32/LoadLibraryA基址

r12 存储 kernel32 基址,通过 GetProcessAddress 将 LoadLibraryA 函数地址存储在 rax:

代码语言:javascript
复制
format PE64 GUI 6.0
entry main

section '.text' executable
main:
    ;write your code here
    xor rax, rax
    sub rsp, 28h                ;reserve stack space for called function
    and rsp, 0fffffffffffffff0h ;make sure stack 16-byte aligned
    mov r12, [gs:60h]           ;peb
    mov r12, [r12 + 0x18]       ;peb->ldr
    mov r12, [r12 + 0x20]       ;peb->ldr->InMemoryOrderModuleList
    mov r12, [r12]              ;2st entry
    mov r15, [r12 + 0x20]       ;ntdll.dll base address!
    mov r12, [r12]              ;3nd entry
    mov r12, [r12 + 0x20]       ;kernel32.dll base address!

    mov rdx, 0xec0e4e8e         ;LoadLibraryA hash from ror13
    mov rcx, r12                ;kernel32 base address
    call GetProcessAddress
    ret

;Hashing section to resolve a function address  
GetProcessAddress:      
    mov r13, rcx                     ;base address of dll loaded 
    mov eax, [r13d + 0x3c]           ;skip DOS header and go to PE header
    mov r14d, [r13d + eax + 0x88]    ;0x88 offset from the PE header is the export table. 
    add r14d, r13d                  ;make the export table an absolute base address and put it in r14d.
    mov r10d, [r14d + 0x18]         ;go into the export table and get the numberOfNames 
    mov ebx, [r14d + 0x20]          ;get the AddressOfNames offset. 
    add ebx, r13d                   ;AddressofNames base. 
find_function_loop: 
    jecxz find_function_finished   ;if ecx is zero, quit :( nothing found. 
    dec r10d                       ;dec ECX by one for the loop until a match/none are found
    mov esi, [ebx + r10d * 4]      ;get a name to play with from the export table. 
    add esi, r13d                  ;esi is now the current name to search on. 
find_hashes:
    xor edi, edi
    xor eax, eax
    cld         
continue_hashing:   
    lodsb                         ;get into al from esi
    test al, al                   ;is the end of string resarched?
    jz compute_hash_finished
    ror dword edi, 0xd            ;ROR13 for hash calculation!
    add edi, eax        
    jmp continue_hashing
compute_hash_finished:
    cmp edi, edx                  ;edx has the function hash
    jnz find_function_loop        ;didn't match, keep trying!
    mov ebx, [r14d + 0x24]        ;put the address of the ordinal table and put it in ebx. 
    add ebx, r13d                 ;absolute address
    xor ecx, ecx                  ;ensure ecx is 0'd. 
    mov cx, [ebx + 2 * r10d]      ;ordinal = 2 bytes. Get the current ordinal and put it in cx. ECX was our counter for which # we were in. 
    mov ebx, [r14d + 0x1c]        ;extract the address table offset
    add ebx, r13d                 ;put absolute address in EBX.
    mov eax, [ebx + 4 * ecx]      ;relative address
    add eax, r13d   
find_function_finished:
    ret

编译:fasm win64_msg.asm 使用 x64dbg 调试查看到获取地址成功:

0x02 GetProcAddreass 获取 API 地址

这个函数里为什么要用 hash 比对,也可以直接 API 名字比对,但是汇编比较麻烦,并且会在生成的二进制文件中出现字符串特征,所以用 hash 比对。

通过对 kernel32.dll 的导出表中记录的 API name 进行 hash 对比,可以找到 LoadLibraryA API 基址,然后就可以利用该函数加载其他 dll 了。

弹消息框需要的是 user32.dll 的 MessageBox,所以我们需要先载入 user32.dll,之后使用上面同样的 hash 比对方法获取 MessageBox API 的地址,关于 API hash怎么获取,可以参考:https://github.com/ihack4falafel/ROR13HashGenerato

0x03 获取 MessageBoxA 地址并弹框

最终代码:

代码语言:javascript
复制
format binary
use64

;format PE64 GUI 6.0
;entry main
;section '.text' executable
;main:
    ;find kernel32 dll base address from peb
    push rbp
    mov rbp, rsp
    sub rsp, 60h                ; reserve stack space for called function
    and rsp, 0fffffffffffffff0h ; make sure stack 16-byte aligned
    mov r12, [gs:60h]           ; peb
    mov r12, [r12 + 0x18]       ; peb->ldr
    mov r12, [r12 + 0x20]       ; peb->ldr->InMemoryOrderModuleList
    mov r12, [r12]              ; 2st entry
    mov r15, [r12 + 0x20]       ; ntdll.dll base address!
    mov r12, [r12]              ; 3nd entry
    mov r12, [r12 + 0x20]       ; kernel32.dll base address!

    ;find LoadLibraryA API address from kernel32.dll
    mov rdx, 0xec0e4e8e         ; LoadLibraryA hash from ror13
    mov rcx, r12                ; kernel32 base address
    call GetProcessAddress      ; LoadLibraryA address -> rax
    mov [rbp-30h], rax
    
    ;use LoadLibraryA to load user32.dll
    jmp GetUser32String         ; call/pop get 'user32.dll' string
jmpFromGetUser32String:
    pop rcx                     ; rcx <- esp <- 'user32.dll'
    call rax                    ; call LoadLibraryA, store base address to rax
   
    ;find MessageBoxA API address from user32.dll
    mov rdx, 0xBC4DA2A8         ; MessageBoxA hash from ror13
    mov rcx, rax                ; user32 base address
    call GetProcessAddress      ; MessageBoxA address -> rax
    
    ;call MessageBoxA API to display message dialog
    mov r9, 0                   ; MS_BUTTEN_OK
    jmp GetTitleString          ; store title string to stack
jmpFromGetTitleString:
    pop r8                      ; get title string from stack top
    jmp GetTextString           ; store text string to stack
jmpFromGetTextString:
    pop rdx                     ; get text string from stack top
    mov rcx, 0                  ; hWnd
    call rax                    ; call MessageBoxA
    
    ;find ExitThread API address from kernel32
    ;mov rdx, 0x60E0CEEF         ; ExitThread hash from ror13
    ;mov rcx, r12                ; kernel32 base address
    ;call GetProcessAddress      ; ExitThread address -> rax
    
    ;load ntdll.dll
    mov rax, [rbp-30h]                     ; rax = address of LoadLibraryA
    jmp GetNtdllString
jmpFromGetNtdllString:
    pop rcx
    call rax
    
    ;find RltExitUserThread API address from ntdll.dll
    mov rdx, 0xFF7F061A
    mov rcx, rax
    call GetProcessAddress
    
    ;call RltExitUserThread API to exit thread
    mov rcx, 0                  ; thread exit code = 0
    call rax                    ; call ExitThread
    
    ;add rsp, 60h                ; restore stack
    ;pop rbp
    ;ret

GetNtdllString:
    call jmpFromGetNtdllString
    db 'ntdll.dll',0

GetUser32String:
    call jmpFromGetUser32String
    db 'user32.dll',0


GetTitleString:
    call jmpFromGetTitleString
    db 'ERROR',0

GetTextString:
    call jmpFromGetTextString
    db 'Hello World!',0

;Hashing section to resolve a function address  
GetProcessAddress:      
    mov r13, rcx                     ;base address of dll loaded 
    mov eax, [r13d + 0x3c]           ;skip DOS header and go to PE header
    mov r14d, [r13d + eax + 0x88]    ;0x88 offset from the PE header is the export table. 
    add r14d, r13d                  ;make the export table an absolute base address and put it in r14d.
    mov r10d, [r14d + 0x18]         ;go into the export table and get the numberOfNames 
    mov ebx, [r14d + 0x20]          ;get the AddressOfNames offset. 
    add ebx, r13d                   ;AddressofNames base. 
find_function_loop: 
    jecxz find_function_finished   ;if ecx is zero, quit :( nothing found. 
    dec r10d                       ;dec ECX by one for the loop until a match/none are found
    mov esi, [ebx + r10d * 4]      ;get a name to play with from the export table. 
    add esi, r13d                  ;esi is now the current name to search on. 
find_hashes:
    xor edi, edi
    xor eax, eax
    cld         
continue_hashing:   
    lodsb                         ;get into al from esi
    test al, al                   ;is the end of string resarched?
    jz compute_hash_finished
    ror dword edi, 0xd            ;ROR13 for hash calculation!
    add edi, eax        
    jmp continue_hashing
compute_hash_finished:
    cmp edi, edx                  ;edx has the function hash
    jnz find_function_loop        ;didn't match, keep trying!
    mov ebx, [r14d + 0x24]        ;put the address of the ordinal table and put it in ebx. 
    add ebx, r13d                 ;absolute address
    xor ecx, ecx                  ;ensure ecx is 0'd. 
    mov cx, [ebx + 2 * r10d]      ;ordinal = 2 bytes. Get the current ordinal and put it in cx. ECX was our counter for which # we were in. 
    mov ebx, [r14d + 0x1c]        ;extract the address table offset
    add ebx, r13d                 ;put absolute address in EBX.
    mov eax, [ebx + 4 * ecx]      ;relative address
    add eax, r13d   
find_function_finished:
    ret

其中 format binaryuse64 表示生成 64 位的 shellcode,如果注释掉,如果换成下面我注释的那四行代表生成 64 位 exe。

加载 shellcode,可以自己写,也可以用这个项目里的 runshc64.exe 测试一下 https://github.com/hasherezade/pe_to_shellcode

0x04 shellcode 退出

shellcode 执行完相应的功能,退出的方式有以下几种:

  • 调用 kernel32!ExitProcess,适合直接终止整个程序
  • 调用 kernel32!ExitThread,适合终止线程
  • ret,正常返回,结束程序由主程序负责

测试线程退出的时候发现,直接汇编调用 kernel32!ExitThread 会导致程序 crash:

代码语言:javascript
复制
;find ExitThread API address from kernel32
mov rdx, 0x60E0CEEF         ; ExitThread hash from ror13
mov rcx, r12                ; kernel32 base address
call GetProcessAddress      ; ExitThread address -> rax

mov rcx, 0                  ; thread exit code = 0
call rax                    ; call ExitThread

由于 kernel32!ExitThread 最终会重定向到 ntdll!RtlExitUserThread 所以改用这个试试:

代码语言:javascript
复制
;load ntdll.dll
mov rax, [rbp-30h]                     ; rax = address of LoadLibraryA
jmp GetNtdllString
jmpFromGetNtdllString:
pop rcx
call rax

;find RltExitUserThread API address from ntdll.dll
mov rdx, 0xFF7F061A
mov rcx, rax
call GetProcessAddress

;call RltExitUserThread API to exit thread
mov rcx, 0                  ; thread exit code = 0
call rax                    ; call ExitThread

这个就没有问题,很神奇,同时简单看了一下 msf 生成 MessageBox 汇编的代码,貌似和 Windows 版本有关系。

还有一个问题,就是如果不使用 API 退出,只是 ret 的话主进程并不能退出,搞不懂:

代码语言:javascript
复制
xor rax, rax
add rsp, 60h                ; restore stack
pop rbp
ret

由 x64dbg 调了一下,发现是堆栈不平衡导致的,为什么会堆栈不平衡?

代码语言:javascript
复制
push rbp
mov rbp, rsp
sub rsp, 60h                ; reserve stack space for called function
and rsp, 0fffffffffffffff0h ; make sure stack 16-byte aligned
;;;;;;;;;;;;
xor rax, rax
add rsp, 60h                ; restore stack
pop rbp
ret

这是由于 and rsp, 0fffffffffffffff0h 这句导致的,在某些情况下会导致 rsp - 8。知道问题根源之后,就想把这句去掉,去掉之后发现 MessageBoxA 调用过程内存访问异常了,纳闷。

最后想了个办法,在 and 指令之前先用 rbp 保存一下当前栈顶,然后到结束直接恢复回去:

代码语言:javascript
复制
push rbp                    ; save rbp original state
mov rbp, rsp
sub rsp, 60h                ; reserve stack space for called function
and rsp, 0fffffffffffffff0h ; make sure stack 16-byte aligned
;;;;;;;;;;;;
xor rax, rax
mov rsp, rbp                ; resotre rsp
pop rbp                     ; restore rbp
ret

这个解决之后,返回到调用 shellcode 之后的地方继续执行,会出现访问异常,这个调了一下,发现是 shellcode 执行过程把 rsi 寄存器改了,所以解决办法就是像 rbp 一样,先保存一下,最后恢复回去:

代码语言:javascript
复制
push rsi                    ; save rbp state
push rbp                    ; save rbp state
mov rbp, rsp
sub rsp, 60h                ; reserve stack space for called function
and rsp, 0fffffffffffffff0h ; make sure stack 16-byte aligned
;;;;;;;;;;;;
xor rax, rax                ; return 0
mov rsp, rbp                ; resotre rsp
pop rbp                     ; restore rbp
pop rsi                     ; restore rsi
ret

最后,完美运行!

0x05 中文弹框

改成 MessageBoxW,他的 hash 是 0xBC4DA2BE,然后使用 fasm 提供的 du 指令,需要包含 encoding\utf8.inc

代码语言:javascript
复制
include 'encoding\utf8.inc'
format binary
use64

;format PE64 GUI 6.0
;entry main
;section '.text' executable
;main:
    ;find kernel32 dll base address from peb
    push r12
    push rdi
    push rdx
    push rcx
    push rbx
    push rbp
    mov rbp, rsp
    sub rsp, 68h                ; reserve stack space for called function
    and rsp, 0fffffffffffffff0h ; make sure stack 16-byte aligned
    mov r12, [gs:60h]           ; peb
    mov r12, [r12 + 0x18]       ; peb->ldr
    mov r12, [r12 + 0x20]       ; peb->ldr->InMemoryOrderModuleList
    mov r12, [r12]              ; 2st entry
    mov r15, [r12 + 0x20]       ; ntdll.dll base address!
    mov r12, [r12]              ; 3nd entry
    mov r12, [r12 + 0x20]       ; kernel32.dll base address!

    ;find LoadLibraryA API address from kernel32.dll
    mov rdx, 0xec0e4e8e         ; LoadLibraryA hash from ror13
    mov rcx, r12                ; kernel32 base address
    call GetProcessAddress      ; LoadLibraryA address -> rax
    mov [rbp-30h], rax
    
    ;use LoadLibraryA to load user32.dll
    jmp GetUser32String         ; call/pop get 'user32.dll' string
jmpFromGetUser32String:
    pop rcx                     ; rcx <- esp <- 'user32.dll'
    call rax                    ; call LoadLibraryA, store base address to rax
   
    ;find MessageBoxW API address from user32.dll
    mov rdx, 0xBC4DA2BE         ; MessageBoxW hash from ror13
    mov rcx, rax                ; user32 base address
    call GetProcessAddress      ; MessageBoxW address -> rax
    
    ;call MessageBoxW API to display message dialog
    mov r9, 0                   ; MS_BUTTEN_OK
    jmp GetTitleString          ; store title string to stack
jmpFromGetTitleString:
    pop r8                      ; get title string from stack top
    jmp GetTextString           ; store text string to stack
jmpFromGetTextString:
    pop rdx                     ; get text string from stack top
    mov rcx, 0                  ; hWnd
    call rax                    ; call MessageBoxW
    
    xor rax, rax
    mov rsp, rbp
    pop rbp
    pop rbx
    pop rcx
    pop rdx
    pop rdi
    pop r12
    ret

GetUser32String:
    call jmpFromGetUser32String
    db 'user32.dll',0


GetTitleString:
    call jmpFromGetTitleString
    du 'ERROR',0

GetTextString:
    call jmpFromGetTextString
    du '资源加载失败!',0

;Hashing section to resolve a function address  
GetProcessAddress:      
    mov r13, rcx                     ;base address of dll loaded 
    mov eax, [r13d + 0x3c]           ;skip DOS header and go to PE header
    mov r14d, [r13d + eax + 0x88]    ;0x88 offset from the PE header is the export table. 
    add r14d, r13d                  ;make the export table an absolute base address and put it in r14d.
    mov r10d, [r14d + 0x18]         ;go into the export table and get the numberOfNames 
    mov ebx, [r14d + 0x20]          ;get the AddressOfNames offset. 
    add ebx, r13d                   ;AddressofNames base. 
find_function_loop: 
    jecxz find_function_finished   ;if ecx is zero, quit :( nothing found. 
    dec r10d                       ;dec ECX by one for the loop until a match/none are found
    mov esi, [ebx + r10d * 4]      ;get a name to play with from the export table. 
    add esi, r13d                  ;esi is now the current name to search on. 
find_hashes:
    xor edi, edi
    xor eax, eax
    cld         
continue_hashing:   
    lodsb                         ;get into al from esi
    test al, al                   ;is the end of string resarched?
    jz compute_hash_finished
    ror dword edi, 0xd            ;ROR13 for hash calculation!
    add edi, eax        
    jmp continue_hashing
compute_hash_finished:
    cmp edi, edx                  ;edx has the function hash
    jnz find_function_loop        ;didn't match, keep trying!
    mov ebx, [r14d + 0x24]        ;put the address of the ordinal table and put it in ebx. 
    add ebx, r13d                 ;absolute address
    xor ecx, ecx                  ;ensure ecx is 0'd. 
    mov cx, [ebx + 2 * r10d]      ;ordinal = 2 bytes. Get the current ordinal and put it in cx. ECX was our counter for which # we were in. 
    mov ebx, [r14d + 0x1c]        ;extract the address table offset
    add ebx, r13d                 ;put absolute address in EBX.
    mov eax, [ebx + 4 * ecx]      ;relative address
    add eax, r13d   
find_function_finished:
    ret

显示正常,nice!

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目录
  • 0x00 设置堆栈
  • 0x01 获取kernel32/LoadLibraryA基址
  • 0x02 GetProcAddreass 获取 API 地址
  • 0x03 获取 MessageBoxA 地址并弹框
  • 0x04 shellcode 退出
  • 0x05 中文弹框
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