java web 获取到当前用户请求的完整url，包括参数

前Thoughtworks-杨焱

发布于 2021-12-08 00:43:56

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代码可运行

文章被收录于专栏：杨焱的专栏杨焱的专栏

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代码可运行

  String url = request.getScheme() + "://" +
                request.getServerName() +
                ("http".equals(request.getScheme()) && request.getServerPort() == 80 || "https".equals(request.getScheme()) && request.getServerPort() == 443 ? "" : ":" + request.getServerPort()) +
                request.getRequestURI() +
                (request.getQueryString() != null ? "?" + request.getQueryString() : "");