leetcode-121. 买卖股票的最佳时机

class Solution {
    public int maxProfit(int[] prices) {
        // 令价格最小值为 Integer.MAX_VALUE
        int minprice = Integer.MAX_VALUE;
        // 令最大收益为 0
        int maxprofit = 0;
        // 循环找出最小的价格并求最大收益
        for (int i = 0; i < prices.length; i++) {
            if (prices[i] < minprice) {
                minprice = prices[i];
            } else if (prices[i] - minprice > maxprofit) {
                maxprofit = prices[i] - minprice;
            }
        }
        return maxprofit;
    }
}