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社区首页 >专栏 >Python统计节假日剩余天数

Python统计节假日剩余天数

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wangmcn
发布于 2022-07-26 08:29:13
发布于 2022-07-26 08:29:13
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文章被收录于专栏:AllTests软件测试AllTests软件测试
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Python统计节假日剩余天数

目录

  • 1、前言
  • 2、倒计时脚本

1、前言

如何快速的想了解距离节假日还有多少天?

接下来使用Python脚本来解决这个问题。

2、倒计时脚本

脚本代码:

代码语言:javascript
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#!/usr/bin/env python
# -*- coding: utf-8 -*-
# 公众号:AllTests软件测试

from colorama import init, Fore
from zhdate import ZhDate
import datetime

def get_week_day(date):
    week_day_dict = {
        0: '星期一',
        1: '星期二',
        2: '星期三',
        3: '星期四',
        4: '星期五',
        5: '星期六',
        6: '星期天',
    }
    day = date.weekday()
    return week_day_dict[day]

def time_parse(today):
    distance_year = (datetime.datetime.strptime(f"{today.year}-01-01", "%Y-%m-%d").date() - today).days
    distance_year = distance_year if distance_year > 0 else (
            datetime.datetime.strptime(f"{today.year + 1}-01-01", "%Y-%m-%d").date() - today).days

    distance_big_year = (ZhDate(today.year, 1, 1).to_datetime().date() - today).days
    distance_big_year = distance_big_year if distance_big_year > 0 else (
            ZhDate(today.year + 1, 1, 1).to_datetime().date() - today).days

    distance_4_5 = (datetime.datetime.strptime(f"{today.year}-04-05", "%Y-%m-%d").date() - today).days
    distance_4_5 = distance_4_5 if distance_4_5 > 0 else (
            datetime.datetime.strptime(f"{today.year + 1}-04-05", "%Y-%m-%d").date() - today).days

    distance_5_1 = (datetime.datetime.strptime(f"{today.year}-05-01", "%Y-%m-%d").date() - today).days
    distance_5_1 = distance_5_1 if distance_5_1 > 0 else (
            datetime.datetime.strptime(f"{today.year + 1}-05-01", "%Y-%m-%d").date() - today).days

    distance_5_5 = (ZhDate(today.year, 5, 5).to_datetime().date() - today).days
    distance_5_5 = distance_5_5 if distance_5_5 > 0 else (
            ZhDate(today.year + 1, 5, 5).to_datetime().date() - today).days

    distance_8_15 = (ZhDate(today.year, 8, 15).to_datetime().date() - today).days
    distance_8_15 = distance_8_15 if distance_8_15 > 0 else (
            ZhDate(today.year + 1, 8, 15).to_datetime().date() - today).days

    distance_10_1 = (datetime.datetime.strptime(f"{today.year}-10-01", "%Y-%m-%d").date() - today).days
    distance_10_1 = distance_10_1 if distance_10_1 > 0 else (
            datetime.datetime.strptime(f"{today.year + 1}-10-01", "%Y-%m-%d").date() - today).days

    # print("距离周末: ", 5 - today.weekday())
    # print("距离元旦: ", distance_year)
    # print("距离大年: ", distance_big_year)
    # print("距离清明: ", distance_4_5)
    # print("距离劳动: ", distance_5_1)
    # print("距离端午: ", distance_5_5)
    # print("距离中秋: ", distance_8_15)
    # print("距离国庆: ", distance_10_1)

    time_ = [
        {"v_": 5 - 1 - today.weekday(), "title": "周末"}, # 距离周末
        {"v_": distance_year, "title": "元旦"}, # 距离元旦
        {"v_": distance_big_year, "title": "过年"}, # 距离过年
        {"v_": distance_4_5, "title": "清明节"}, # 距离清明
        {"v_": distance_5_1, "title": "劳动节"}, # 距离劳动
        {"v_": distance_5_5, "title": "端午节"}, # 距离端午
        {"v_": distance_8_15, "title": "中秋节"}, # 距离中秋
        {"v_": distance_10_1, "title": "国庆节"}, # 距离国庆
    ]

    time_ = sorted(time_, key=lambda x: x['v_'], reverse=False)
    return time_

def countdown():
    init(autoreset=True)
    today = datetime.date.today()
    now_ = f"{today.year}年{today.month}月{today.day}日"
    week_day_ = get_week_day(today)
    print(f'\n\t\t {Fore.GREEN}{now_} {week_day_}')

    str_ = '''
         开始!
    '''
    print(f'{Fore.RED}{str_}')

    time_ = time_parse(today)
    for t_ in time_:
        print(f'\t\t {Fore.RED}距离{t_.get("title")}还有: {t_.get("v_")}天')
    tips_ = '''
         结束!
    '''
    print(f'{Fore.RED}{tips_}')

    print(f'\t\t{Fore.CYAN} 公众号:AllTests软件测试\n')

if __name__ == '__main__':
    countdown()

在PyCharm上执行结果:

在终端上执行结果:

本文参与 腾讯云自媒体同步曝光计划,分享自微信公众号。
原始发表:2022-02-14,如有侵权请联系 cloudcommunity@tencent.com 删除

本文分享自 AllTests软件测试 微信公众号,前往查看

如有侵权,请联系 cloudcommunity@tencent.com 删除。

本文参与 腾讯云自媒体同步曝光计划  ,欢迎热爱写作的你一起参与!

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