SQL如何只让特定列中只显示一行数据
我们如果在某个表里面，如何让其中某列的其中一行数据，只是显示一次呢？
示例表
StudentID | Last_Name | First_Name | Gender | GradeLevel | Class | Pupil_Email | Relationship | Pupil_Parent_Email |
|---|---|---|---|---|---|---|---|---|
5013 | Wang | Zack | M | Grade 9 Senior | SG9 B | 5013@example.com | 爸爸 | 5013a@qq.com |
5013 | Wang | Zack | M | Grade 9 Senior | SG9 B | 5013@example.com | 妈妈 | 5013b@qq.com |
5014 | Liu | Aileen | F | Grade 2 Bilingual | BG2 D | 5014@example.com | 爸爸 | 5014a@qq.com |
5014 | Liu | Aileen | F | Grade 2 Bilingual | BG2 D | 5014@example.com | 妈妈 | 5014b@qq.com |
5014 | Liu | Aileen | F | Grade 2 Bilingual | BG2 D | 5014@example.com | 妈妈 | 5014b@qq.com |
5017 | Ying | Eason | F | Grade 9 Senior | SG9 A | 5017@example.com | 爸爸 | 5017e@qq.com |
5017 | Ying | Eason | F | Grade 9 Senior | SG9 A | 5017@example.com | 爸爸 | 5017e@qq.com |
5029 | Yan | Yuki | M | Grade 3 Bilingual | BG3 H | 5029@example.com | 爸爸 | 5029a@qq.com |
5029 | Yan | Yuki | M | Grade 3 Bilingual | BG3 H | 5029@example.com | 妈妈 | 5029b1@qq.com |
5029 | Yan | Yuki | M | Grade 3 Bilingual | BG3 H | 5029@example.com | 妈妈 | 5029b2@qq.com |
5029 | Yan | Yuki | M | Grade 3 Bilingual | BG3 H | 5029@example.com | 妈妈 | 5029b3@qq.com |
解析
如你所见，学号5014和5029的学生妈妈出现多次，而5017学生同样数据显示了2次。那么我们如何让其数据，也就是“妈妈”，只显示其中一个呢?
Step 1 DISTINCT
DISTINCT是可以将重复数据去除，只显示一行。但是这个是全部Select表的重复数据。所以如果想要“妈妈”信息只是显示一条是不可行的。
我们先将5017学生的重复数据去除
Step 2 MIN()和Group By
我们将想要只显示一条数据的列进行MIN()或MAX() 【根据字母大小显示第一条】
Group By后面跟着所有除去MIN()那一列的数据即可。
Select DISTINCT
StudentID
,Last_Name
,First_Name
,Gender
,GradeLevel
,Class
,Pupil_Email
,Relationship
,MIN(Pupil_Parent_Email) AS Pupil_Parent_Email
From TableA
Group By StudentID
,Last_Name
,First_Name
,Gender
,GradeLevel
,Class
,Pupil_Email
,Relationship结果：
StudentID | Last_Name | First_Name | Gender | GradeLevel | Class | Pupil_Email | Relationship | Pupil_Parent_Email |
|---|---|---|---|---|---|---|---|---|
5013 | Wang | Zack | M | Grade 9 Senior | SG9 B | 5013@example.com | 爸爸 | 5013a@qq.com |
5013 | Wang | Zack | M | Grade 9 Senior | SG9 B | 5013@example.com | 妈妈 | 5013b@qq.com |
5014 | Liu | Aileen | F | Grade 2 Bilingual | BG2 D | 5014@example.com | 爸爸 | 5014a@qq.com |
5014 | Liu | Aileen | F | Grade 2 Bilingual | BG2 D | 5014@example.com | 妈妈 | 5014b@qq.com |
5017 | Ying | Eason | F | Grade 9 Senior | SG9 A | 5017@example.com | 爸爸 | 5017e@qq.com |
5029 | Yan | Yuki | M | Grade 3 Bilingual | BG3 H | 5029@example.com | 爸爸 | 5029a@qq.com |
5029 | Yan | Yuki | M | Grade 3 Bilingual | BG3 H | 5029@example.com | 妈妈 | 5029b1@qq.com |
上面我们所有的工作已经完成了！如果我想要将该表的邮箱行列进行互换呢？
如果想要互换，当然可以直接通过PIVOT来实现，但是如果我们想要先计算学生有多少个长辈邮箱，且每个长辈邮箱只显示一个，我们应该怎么做呢？
Step 3 ROW_NUMBER()
SQL Server Tutorial ROW_NUMBER()教学
我们可以根据父母关系邮箱来进行排序
以下是基本用法
ROW_NUMBER() OVER (
Order By TableA.ColumnID
) AS Count_Row_No通过上面的方式，只是计算总数的行数(Row Number), 在实际使用中，我们更多是根据某一列的数据来计算他的数据出现的次数。
例如：
ROW_NUMBER() OVER (
PARTITION By TableA.ColumnID
Order By TableA.ColumnID
) AS Count_Row_No这是根据ColumnID，看看同一ColumnID出现的次数。
所以本案例的做法如下：
Select DISTINCT
StudentID
,Last_Name
,First_Name
,Gender
,GradeLevel
,Class
,Pupil_Email
,Relationship
,MIN(Pupil_Parent_Email) AS Pupil_Parent_Email
,ROW_NUMBER() OVER (
PARTITION By TableA.StudentID
Order By TableA.StudentID
) AS Count_Row_No
From TableA
Group By StudentID
,Last_Name
,First_Name
,Gender
,GradeLevel
,Class
,Pupil_Email
,RelationshipExcel实现方式
实际上，Excel可以通过非常简单的方法实现计数。=COUNTIF(E 2:
Step 4 PIVOT
最后，我们需要将邮箱从列变成行
Select * From
(
Select DISTINCT
StudentID
,Last_Name
,First_Name
,Gender
,GradeLevel
,Class
,Pupil_Email
/**
我们需要将关系，从表中隐藏，这样才能在PIVOT中将行变成列
**/
--,Relationship
,MIN(Pupil_Parent_Email) AS Pupil_Parent_Email
,ROW_NUMBER() OVER (
PARTITION By TableA.StudentID
Order By TableA.StudentID
) AS RelationEmailCount
From TableA
Group By StudentID
,Last_Name
,First_Name
,Gender
,GradeLevel
,Class
,Pupil_Email
,Relationship
) As BaseTable
PIVOT (
MAX(Pupil_Parent_Email)
FOR [RelationEmailCount] in ([1],[2])
) As Result
Order By Last_Name结果如下：
StudentID | Last_Name | First_Name | Gender | GradeLevel | Class | Pupil_Email | 1 | 2 |
|---|---|---|---|---|---|---|---|---|
5014 | Liu | Aileen | F | Grade 2 Bilingual | BG2 D | 5014@example.com | 5014a@qq.com | 5014b@qq.com |
5013 | Wang | Zack | M | Grade 9 Senior | SG9 B | 5013@example.com | 5013a@qq.com | 5013b@qq.com |
5029 | Yan | Yuki | M | Grade 3 Bilingual | BG3 H | 5029@example.com | 5029a@qq.com | 5029b1@qq.com |
5017 | Ying | Eason | F | Grade 9 Senior | SG9 A | 5017@example.com | 5017e@qq.com | NULL |
STRING_AGG的实现方式
StudentID | Last_Name | First_Name | Gender | GradeLevel | Class | Pupil_Email | Relationship | Pupil_Parent_Email |
|---|---|---|---|---|---|---|---|---|
5013 | Wang | Zack | M | Grade 9 Senior | SG9 B | 5013@example.com | 爸爸 | 5013a@qq.com |
5013 | Wang | Zack | M | Grade 9 Senior | SG9 B | 5013@example.com | 妈妈 | 5013b@qq.com |
5014 | Liu | Aileen | F | Grade 2 Bilingual | BG2 D | 5014@example.com | 爸爸 | 5014a@qq.com |
5014 | Liu | Aileen | F | Grade 2 Bilingual | BG2 D | 5014@example.com | 妈妈 | 5014b@qq.com |
5017 | Ying | Eason | F | Grade 9 Senior | SG9 A | 5017@example.com | 爸爸 | 5017e@qq.com |
5029 | Yan | Yuki | M | Grade 3 Bilingual | BG3 H | 5029@example.com | 爸爸 | 5029a@qq.com |
5029 | Yan | Yuki | M | Grade 3 Bilingual | BG3 H | 5029@example.com | 妈妈 | 5029b1@qq.com |
Select
StudentID
,Last_Name
,First_Name
,Gender
,GradeLevel
,Class
,Pupil_Email
--,Relationship
,STRING_AGG(Pupil_Parent_Email, ',') AS Pupil_Parent_Email
From TableA
Group By StudentID
,Last_Name
,First_Name
,Gender
,GradeLevel
,Class
,Pupil_Email
,RelationshipStudentID | Last_Name | First_Name | Gender | GradeLevel | Class | Pupil_Email | Pupil_Parent_Email |
|---|---|---|---|---|---|---|---|
5013 | Wang | Zack | M | Grade 9 Senior | SG9 B | 5013@example.com | 5013a@qq.com ,5013b@qq.com |
5014 | Liu | Aileen | F | Grade 2 Bilingual | BG2 D | 5014@example.com | 5014a@qq.com ,5014b@qq.com |
5017 | Ying | Eason | F | Grade 9 Senior | SG9 A | 5017@example.com | 5017e@qq.com |
5029 | Yan | Yuki | M | Grade 3 Bilingual | BG3 H | 5029@example.com | 5029a@qq.com ,5029b1@qq.com |
然后可以通过逗号的分割进行新建一行的分割列
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