使用python轻松实现21点小游戏

import random

# 创建一副扑克牌
cards = ["A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K"] * 4

# 计算牌的点数
def calculate_score(hand):
    score = 0
    num_aces = hand.count("A")
    
    for card in hand:
        if card in ["J", "Q", "K"]:
            score += 10
        elif card == "A":
            score += 11
        else:
            score += int(card)
    
    # 调整A的点数
    while score > 21 and num_aces > 0:
        score -= 10
        num_aces -= 1
    
    return score

# 发牌
def deal_card():
    return cards.pop(random.randint(0, len(cards)-1))

# 游戏主循环
def play_game():
    player_hand = []
    dealer_hand = []
    
    # 发两张牌给玩家和庄家
    for _ in range(2):
        player_hand.append(deal_card())
        dealer_hand.append(deal_card())
    
    game_over = False
    
    while not game_over:
        player_score = calculate_score(player_hand)
        dealer_score = calculate_score(dealer_hand)
        
        print(f"玩家牌: {player_hand}, 点数: {player_score}")
        print(f"庄家牌: {dealer_hand[0]}")
        
        if player_score == 21 or dealer_score == 21 or len(player_hand) == 5:
            game_over = True
        else:
            choice = input("是否继续抽牌? 输入 'y' 继续抽牌，输入 'n' 停止抽牌: ")
            
            if choice == "y":
                player_hand.append(deal_card())
            else:
                game_over = True
    
    # 庄家抽牌
    while dealer_score < 17 and dealer_score < player_score:
        dealer_hand.append(deal_card())
        dealer_score = calculate_score(dealer_hand)
    
    print(f"玩家牌: {player_hand}, 点数: {player_score}")
    print(f"庄家牌: {dealer_hand}, 点数: {dealer_score}")
    print("游戏结束！")
    
    if player_score > 21 or (dealer_score <= 21 and dealer_score > player_score):
        print("庄家获胜！")
    elif dealer_score > 21 or player_score > dealer_score:
        print("玩家获胜！")
    else:
        print("平局！")

# 开始游戏
play_game()