作为一名开发工程师,你首先应该想如何设计这个项目,以扫雷为例,首先,你要打印菜单,让用户可以选择玩或退出游戏,同时满足选手还想继续玩一把的需求,所以我们选择do_while循环结构,同时打印菜单选择Switch的分支结构,其次工程师需打印棋盘,对棋盘初始化,为保持棋盘的神秘感,我们可以使用字符数组让他们全部初始化为*,其次我们应该设置雷,用随机函数rand()随机设置10个雷,最后用FindMine()函数排查雷,输入坐标想,x,y用mine[x][y]判断是不是雷,若果是则返回周围八个坐标的雷数,用GetMineCount(统计周围的个数)。当然扫雷还有更难的模式本人水平有限,若有不足,请各位大佬赐教。
#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#define ROW 9
#define COL 9
#define ROWS ROW+2
#define COLS COL+2
#define EASY_COUNT 10
#include<stdlib.h>
#include<time.h>
//初始化棋盘
void InitBoard(char board[ROWS][COLS],int rows,int cols,char set);
//打印棋盘
void DisplayBoard(char board[ROWS][COLS], int row, int col);
//布置雷
void SetMine(char mine[ROWS][COLS], int row, int col);
//排查雷
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);
void game()
{
char mine[ROWS][COLS] = { 0 };//存放雷的信息
char show[ROWS][COLS] = { 0 };//存放好布置好雷的信息
//初始化棋盘
InitBoard(mine, ROWS, COLS, '0');
InitBoard(show, ROWS, COLS, '*');
//打印棋盘
DisplayBoard(show, ROW, COL);
//布置雷
SetMine(mine, ROW, COL);
//DisplayBoard(mine, ROW, COL);
//排查雷
FindMine(mine, show, ROW, COL);
}
//初始化棋盘
void InitBoard(char board[ROWS][COLS], int rows, int cols, char set)
{
int i = 0;
for (i = 0; i < rows; i++)
{
int j = 0;
for (j = 0; j < cols; j++)
{
board[i][j] = set;
}
}
}
//打印棋盘
void DisplayBoard(char board[ROWS][COLS], int row, int col)
{
int i = 0;
printf("********扫雷*******\n");
for (i = 0; i <= row; i++)
printf("%d ", i);
printf("\n");
for (i = 1; i <= row; i++)
{
int j = 0;
printf("%d ", i);
for (j = 1; j <= col; j++)
{
printf("%c ",board[i][j]);
}
printf("\n");
}
}
//布置雷
void SetMine(char mine[ROWS][COLS], int row, int col)
{
int x = 0;
int y = 0;
int count = EASY_COUNT;
while (count)
{
x = rand() % row + 1;
y = rand() % col + 1;
if (mine[x][y] != '1')
{
mine[x][y] = '1';
count--;
}
}
}
int GetMineCount(char mine[ROWS][COLS], int x, int y)
{
return mine[x - 1][y - 1] +
mine[x - 1][y] +
mine[x - 1][y + 1] +
mine[x][y - 1] +
mine[x][y + 1] +
mine[x + 1][y - 1] +
mine[x + 1][y] +
mine[x + 1][y + 1]-8*'0';
}
//排查雷
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
int x = 0;
int y = 0;
int win = 0;
while (win<row*col-EASY_COUNT)
{
printf("请输入要排查的坐标:>");
scanf("%d%d", &x, &y);
if (x >= 1 && x <= row && y >= 1 && y <= col)
{
if (mine[x][y] == '1')
{
printf("很遗憾,你踩雷了,退出游戏!\n");
DisplayBoard(mine, ROW, COL);
break;
}
else
{
int count = GetMineCount(mine, x, y);
show[x][y] = count + '0';
DisplayBoard(show, ROW, COL);
win++;
}
}
else
{
printf("输入的坐标非法,请重新输入!\n");
}
}
if (win == col * row - EASY_COUNT)
{
printf("恭喜你,排雷成功!\n");
DisplayBoard(mine, ROW, COL);
}
}
void menu()
{
printf("**************************************\n");
printf("****************1. play ************\n");
printf("****************0. exit ************\n");
printf("**************************************\n");
}
void test()
{
int input = 0;
srand((unsigned int) time(NULL));
do {
menu();
printf("请选择:>");
scanf("%d", &input);
switch (input)
{
case 1:
game();
break;
case 0:
printf("退出游戏!\n");
break;
default :
printf("选择错误,请重新选择!\n");
}
} while (input);
}
#include<stdio.h>
int main()
{
test();
return 0;
}