C++ 如何实现线程池？给出大体思路？

#include <iostream>
#include <thread>
#include <vector>
#include <queue>
#include <functional>
#include <future>
#include <atomic>
#include <mutex>
#include <condition_variable>

class ThreadPool {
public:
    ThreadPool(size_t threads) : stop(false) {
        for (size_t i = 0; i < threads; ++i) {
            workers.emplace_back([this] {
                while (true) {
                    std::function<void()> task;
                    {
                        std::unique_lock<std::mutex> lock(this->queue_mutex);
                        this->condition.wait(lock, [this] { return this->stop || !this->tasks.empty(); });
                        if (this->stop && this->tasks.empty()) {
                            return;
                        }
                        task = std::move(this->tasks.front());
                        this->tasks.pop();
                    }
                    task();
                }
            });
        }
    }

    ~ThreadPool() {
        {
            std::unique_lock<std::mutex> lock(queue_mutex);
            stop = true;
        }
        condition.notify_all();
        for (std::thread &worker : workers) {
            worker.join();
        }
    }

    template<class F, class... Args>
    auto enqueue(F&& f, Args&&... args) -> std::future<decltype(f(args...))> {
        using return_type = decltype(f(args...));
        auto task = std::make_shared<std::packaged_task<return_type()>>(std::bind(std::forward<F>(f), std::forward<Args>(args)...));

        std::future<return_type> res = task->get_future();
        {
            std::unique_lock<std::mutex> lock(queue_mutex);

            // 不允许加入新任务
            if (stop) {
                throw std::runtime_error("enqueue on stopped ThreadPool");
            }

            tasks.emplace([task]() { (*task)(); });
        }
        condition.notify_one();
        return res;
    }

private:
    std::vector<std::thread> workers;
    std::queue<std::function<void()>> tasks;

    std::mutex queue_mutex;
    std::condition_variable condition;
    std::atomic<bool> stop;
};

// 示例任务函数
void taskFunction(int id) {
    std::cout << "Task " << id << " is running on thread " << std::this_thread::get_id() << std::endl;
}

int main() {
    ThreadPool pool(4);

    for (int i = 0; i < 10; ++i) {
        pool.enqueue(taskFunction, i);
    }

    return 0;
}