我有以下jQuery代码:
我的Html:
<div class="input-group top_buffer_small">
<label class="col-md-3 col-sm-3 text_right top_buffer_mini">Available Colors:</label>
<div class="col-md-9 col-sm-9 text_right">
<table id="availColors" align="center">
<?php
//instantiate color class
$colors = $Item->getColors();
$colorCount = $Item->getColorCount();
if($colorCount > 0){
//create a mod since we only want to show 4 colors per row.
$remainder = $colorCount%4;
$x=0; //counter variable
if(is_array($colors)){
foreach ($colors as $key=>$value){
foreach ($value as $color) {
if($remainder == 0){
//if we are at 0, make a new row
echo "<tr>";
}
//print_r($Item->getProductVariations($color));
?>
<td style="background-color:#<?php echo $color;?>" data-pictures="<?php echo htmlspecialchars(json_encode($Item->getProductVariations($color))); ?>" data-directory="<?php echo $pictures.$category.'/'.$itemid.'_'.$itemName.'/';?>"></td>
<?php
if($remainder == 3){
//end the row
echo "</tr>";
}
//$x++;
}
}
}
}
?>
</table>
</div>
</div>基本上,我正在尝试获取从传递到我的javascript的数组值。在我得到这些值之后,我试图让所有的图像缩略图在单击一种颜色时变成图片。
这是我打算更改图片缩略图的div:
<div class="row">
<div class="featured_container_small" id="productThumbnails">
<h5>Other Views</h5>
<div class="col-md-3 buffer_bottom"><img src="http://placehold.it/80x100" alt="" class=" center_image responsive_image"></div>
<!-- <div class="col-md-3 buffer_bottom"><img src="<?php echo $pictures.$category.'/'.$itemid.'_'.$itemName.'/'.$smallimage1?>" class=" center_image responsive_image"></div> -->
<div class="col-md-3 buffer_bottom"><img src="http://placehold.it/80x100" alt="" class=" center_image responsive_image"></div>
<div class="col-md-3 buffer_bottom"><img src="http://placehold.it/80x100" alt="" class=" center_image responsive_image"></div>
<div class="col-md-3 buffer_bottom"><img src="http://placehold.it/80x100" alt="" class=" center_image responsive_image"></div>
</div>
<div class="row">
<div class="col-md-12"><nbsp></nbsp></div>
</div>
<div class="clear"></div>
</div>下面是我的jquery:
$(function(){
$("#availColors td").click(function(){
var imageDirectory = $(this).attr('data-directory');
var pictures = $(this).attr('data-pictures');
var pictureArray = JSON.parse(pictures);
var productThumbnails = $("#productThumbnails img");
var thumbnailCount = productThumbnails.length;
var keys = Object.keys(pictureArray);
var pic = "";
var src="";
for (var i = 0; i < keys.length; i++) {
pic = pictureArray[keys[i]];
productThumbnails[i].attr("src",imageDirectory+pic+".jpg");
}
});
});当我执行单击函数时,返回一个错误消息"undefined is not a function“。
我不知道它为什么要这么做。请帮帮忙。
发布于 2014-07-15 15:57:52
当您遍历图像集合时,productThumbnails[i]返回底层的HTMLImageElement,它不提供attr()方法。试着用jQuery来包装它:
$(productThumbnails[i]).attr("src",imageDirectory+pic+".jpg");此外,在使用jQuery时,访问与DOM元素关联的任意数据的最佳方法是使用data()方法:
var imageDirectory = $(this).data('directory');
var pictures = $(this).data('pictures');作为额外的好处,您还将获得开箱即用的JSON反序列化,并且不需要JSON.parse()
var pictureArray = $(this).data('pictures');https://stackoverflow.com/questions/24752565
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