blocks|key|2360160|text|尝试下面的语法。我希望它能帮上忙|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2360161|https://www.google.com/maps/place/?q=place_id:ChIJp4JiUCNP0xQR1JaSjpW_Hms|code-block|syntax|javascript|2360162|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try below syntax. I hope it helps

<pre><code>https://www.google.com/maps/place/?q=place_id:ChIJp4JiUCNP0xQR1JaSjpW_Hms
</code></pre>

blocks|key|4472818|text|这是一个官方url，用于搜索placeId，如果placeId不存在，它会回退到address|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4472819|https://www.google.com/maps/search/?api=1&query=<address>&query_place_id=<placeId>|4472820|无需令牌，适用于安卓、iOS+(以及iOS+11)和网络|4472821|entityMap^0|E|7|O|7|14|7|0|0|2A|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@$9|M|A|N|B|C]|$9|O|A|P|B|C]|$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|V|8|@]|D|@]|E|$]]|$1|J|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|K|$]]

Here is an official url to search for a <code>placeId</code> with a fallback to an <code>address</code> if the <code>placeId</code> does not exist

<code>https://www.google.com/maps/search/?api=1&amp;query=&lt;address&gt;&amp;query_place_id=&lt;placeId&gt;</code>

no token required, works on Android, iOS (as well as iOS 11) and web

blocks|key|2360095|text|有一种方法可以始终获得正确的URL，但它确实需要额外的请求。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2360096|您可以通过https://maps.googleapis.com/maps/api/place/details/json?key=YOURAPIKEY&placeid=THEPLACEID使用place_id来获取地点详细信息|offset|length|style|CODE|2360097|从那里得到的响应有一个'result‘字段，它总是打开正确的位置。例如：https://maps.google.com/?cid=10254754059248426663|2360098|entityMap^0|0|5|2H|0|10|1D|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@$D|N|E|O|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|P|8|@$D|Q|E|R|F|G]]|9|@]|A|$]]|$1|J|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|K|$]]

There is a way of always getting the right URL but it does require an additional request.

You can use the place_id to get the place details with
<code>https://maps.googleapis.com/maps/api/place/details/json?key=YOURAPIKEY&amp;placeid=THEPLACEID</code>

The response from that has a ['result']['url'] field which always opens up the right place. 
eg. <code>https://maps.google.com/?cid=10254754059248426663</code>

blocks|key|4472711|text|在https://www.google.com/maps/place上没有关于预期参数的文档，所以这可能只是一种变通方法(至少目前对我来说是有效的)。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4472712|以下URL格式似乎在大多数情况下都能提供所需的结果：|4472713|https://www.google.com/maps/place/[place-name]/@[latitude],[longitude],[zoom]z/|code-block|syntax|javascript|4472714|您可以根据地名和地点几何创建此URL|4472715|​|4472716|function+initialize()+{
++var+ac+=+new+google.maps.places.Autocomplete(document.getElementById('pac'));
++google.maps.event.addListener(ac,+'place_changed',+function()+{
++++var+place+=+this.getPlace(),
++++++link+=+document.getElementById('link');
++++if+(!place.geometry)+{
++++++link.textContent+=+'';
++++}+else+{
++++++var+zoom+=+17,
++++++++url+=+'https://www.google.com/maps/place/'+%2B
++++++++encodeURIComponent(place.name)+%2B+'/@'+%2B
++++++++place.geometry.location.toUrlValue()+%2B+','+%2B
++++++++zoom+%2B+'z/';
++++++link.href+=+link.textContent+=+url;

++++}

++});
}
google.maps.event.addDomListener(window,+'load',+initialize);|4472717|<script+type="text/javascript"+src="https://maps.googleapis.com/maps/api/js?v=3&libraries=places">
</script>
<input+id="pac"+/>
 
<a+id="link"++href=""+target="_blank"></a>|4472718|4472719|entityMap|0|LINK|mutability|MUTABLE|url|https://www.google.com/maps/place^0|1|X|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|11|8|@]|9|@$A|12|B|13|1|14]]|C|$]]|$1|D|3|E|5|6|7|15|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|16|8|@]|9|@]|C|$I|J]]|$1|K|3|L|5|6|7|17|8|@]|9|@]|C|$]]|$1|M|3|N|5|6|7|18|8|@]|9|@]|C|$]]|$1|O|3|P|5|H|7|19|8|@]|9|@]|C|$I|J]]|$1|Q|3|R|5|H|7|1A|8|@]|9|@]|C|$I|J]]|$1|S|3|N|5|6|7|1B|8|@]|9|@]|C|$]]|$1|T|3|-4|5|6|7|1C|8|@]|9|@]|C|$]]]|U|$V|$5|W|X|Y|C|$Z|10]]]]

There is no documentation for the expected parameters on <a href="https://www.google.com/maps/place" rel="noreferrer">https://www.google.com/maps/place</a> , so this may only be a workaround(at least it currently works for me).

The following URL-format seems to give the desired result in most cases:

<pre><code>https://www.google.com/maps/place/[place-name]/@[latitude],[longitude],[zoom]z/
</code></pre>

You may create this URL based on the place-name and the place-geometry

<div class="snippet" data-lang="js" data-hide="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>function initialize() {
 var ac = new google.maps.places.Autocomplete(document.getElementById('pac'));
 google.maps.event.addListener(ac, 'place_changed', function() {
 var place = this.getPlace(),
 link = document.getElementById('link');
 if (!place.geometry) {
 link.textContent = '';
 } else {
 var zoom = 17,
 url = 'https://www.google.com/maps/place/' +
 encodeURIComponent(place.name) + '/@' +
 place.geometry.location.toUrlValue() + ',' +
 zoom + 'z/';
 link.href = link.textContent = url;

 }

 });
}
google.maps.event.addDomListener(window, 'load', initialize);</code></pre>
<pre class="snippet-code-html lang-html prettyprint-override"><code>&lt;script type="text/javascript" src="https://maps.googleapis.com/maps/api/js?v=3&amp;libraries=places"&gt;
&lt;/script&gt;
&lt;input id="pac" /&gt;
&lt;br/&gt;
&lt;a id="link" href="" target="_blank"&gt;&lt;/a&gt;</code></pre>
</div>
</div>

blocks|key|1797377|text|您可以使用google+embed+API，并将src作为链接:例如：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1797378|+https://www.google.com/maps/embed/v1/place?key=YOUR_API_KEY
++&q=place_id:YOUR_PLACE_ID|code-block|syntax|javascript|1797379|文档：https://developers.google.com/maps/documentation/embed/guide#place_mode|offset|length|1797380|entityMap|0|LINK|mutability|MUTABLE|url|https://developers.google.com/maps/documentation/embed/guide#place_mode^0|0|0|3|1Z|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

You can use google embed API, and take src as a link:
eg: 

<pre><code> https://www.google.com/maps/embed/v1/place?key=YOUR_API_KEY
 &amp;q=place_id:YOUR_PLACE_ID
</code></pre>

Docs:
<a href="https://developers.google.com/maps/documentation/embed/guide#place_mode" rel="nofollow noreferrer">https://developers.google.com/maps/documentation/embed/guide#place_mode</a>

blocks|key|1800723|text|您可以使用google+embed+API，并将src作为链接:例如：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1800724|https://maps.googleapis.com/maps/api/place/details/json?place_id=ChIJN1t_tDeuEmsRUsoyG83frY4&key=YOUR_API_KEY|offset|length|1800725|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|31|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@$D|O|E|P|1|Q]]|A|$]]|$1|F|3|-4|5|6|7|R|8|@]|9|@]|A|$]]]|G|$H|$5|I|J|K|A|$L|C]]]]

You can use google embed API, and take src as a link: eg:

<a href="https://maps.googleapis.com/maps/api/place/details/json?place_id=ChIJN1t_tDeuEmsRUsoyG83frY4&amp;key=YOUR_API_KEY" rel="nofollow noreferrer">https://maps.googleapis.com/maps/api/place/details/json?place_id=ChIJN1t_tDeuEmsRUsoyG83frY4&amp;key=YOUR_API_KEY</a>

blocks|key|1800729|text|在没有place_id的情况下，什么对我有用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1800730|https://www.google.com/maps/search/<search+term>/@<coordinates>,<zoom+level>z|code-block|syntax|javascript|1800731|示例|1800732|https://www.google.com/maps/search/Jouvay%2BNight%2BClub/@40.6961111,-73.8041667,15z|1800733|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

What worked for me without place_id
<pre><code>https://www.google.com/maps/search/&lt;search term&gt;/@&lt;coordinates&gt;,&lt;zoom level&gt;z
</code></pre>
Example
<pre><code>https://www.google.com/maps/search/Jouvay+Night+Club/@40.6961111,-73.8041667,15z
</code></pre>

HeIIo, using google map API with search I'm able to find a certain place and then store it's details. However, the array doesn't contain google maps link which would open this place on google maps. 

Via API I receive place_id which, as I feel, should be enough to build a full google maps link; however, I can't find a way to do that. Can anyone advise me on how to do that.

Thank you for your time.

Getting Google Maps link from place_id

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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HeIIo，使用谷歌地图API进行搜索，我能够找到某个地方，然后存储它的详细信息。然而，该数组不包含google地图链接，该链接将在google地图上打开此位置。通过API，我收到了place_id，因为我觉得它应该足以构建一个完整的谷歌地图链接；然而，我找不到这样做的方法。有没有人能建议我怎么做。谢谢您抽时间见我。

问从place_id获取谷歌地图链接
EN

回答 7

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