正如标题所述。我尝试了google.maps.places.RankBy.PROMINENCE
(默认),并将半径设置为50000,结果返回了20个结果。但当我尝试完全相同的搜索时,减去文档中的半径,并且使用google.maps.places.RankBy.DISTANCE
,我只返回我所在位置的短半径内的3个结果。谁能解释一下为什么会发生这种情况,以及如何根据距离进行附近的搜索并获得完整的结果。也许我只是做错了什么。谢谢。
下面的代码使用google.maps.places.RankBy.PROMINENCE
返回20个结果
var map;
var infowindow;
function initMap() {
var location = {lat: 43.139387, lng: -80.264425};
map = new google.maps.Map(document.getElementById('map'), {
center: location,
zoom: 9
});
infowindow = new google.maps.InfoWindow();
var service = new google.maps.places.PlacesService(map);
service.nearbySearch({
location: location,
radius: 50000,
types: ['police'],
// rankBy: google.maps.places.RankBy.DISTANCE
}, callback);
}
function callback(results, status) {
if (status === google.maps.places.PlacesServiceStatus.OK) {
for (var i = 0; i < results.length; i++) {
createMarker(results[i]);
}
}
}
function createMarker(place) {
var placeLoc = place.geometry.location;
var marker = new google.maps.Marker({
map: map,
position: place.geometry.location
});
google.maps.event.addListener(marker, 'click', function() {
infowindow.setContent(place.name);
infowindow.open(map, this);
});
}
<!DOCTYPE html>
<html>
<head>
<title>Place searches</title>
<meta name="viewport" content="initial-scale=1.0, user-scalable=no">
<meta charset="utf-8">
<style>
html, body {
height: 100%;
margin: 0;
padding: 0;
}
#map {
height: 100%;
}
</style>
</head>
<body>
<div id="map"></div>
<script src="https://maps.googleapis.com/maps/api/js?sensor=false&signed_in=true&libraries=places&callback=initMap" async defer></script>
</body>
</html>
当使用google.maps.places.RankBy.DISTANCE
时,下面的代码只返回3个结果
var map;
var infowindow;
function initMap() {
var location = {lat: 43.139387, lng: -80.264425};
map = new google.maps.Map(document.getElementById('map'), {
center: location,
zoom: 9
});
infowindow = new google.maps.InfoWindow();
var service = new google.maps.places.PlacesService(map);
service.nearbySearch({
location: location,
// radius: 50000,
types: ['police'],
rankBy: google.maps.places.RankBy.DISTANCE
}, callback);
}
function callback(results, status) {
if (status === google.maps.places.PlacesServiceStatus.OK) {
for (var i = 0; i < results.length; i++) {
createMarker(results[i]);
}
}
}
function createMarker(place) {
var placeLoc = place.geometry.location;
var marker = new google.maps.Marker({
map: map,
position: place.geometry.location
});
google.maps.event.addListener(marker, 'click', function() {
infowindow.setContent(place.name);
infowindow.open(map, this);
});
}
<!DOCTYPE html>
<html>
<head>
<title>Place searches</title>
<meta name="viewport" content="initial-scale=1.0, user-scalable=no">
<meta charset="utf-8">
<style>
html, body {
height: 100%;
margin: 0;
padding: 0;
}
#map {
height: 100%;
}
</style>
</head>
<body>
<div id="map"></div>
<script src="https://maps.googleapis.com/maps/api/js?sensor=false&signed_in=true&libraries=places&callback=initMap" async defer></script>
</body>
</html>
发布于 2015-12-23 01:23:15
显着性代码的radius
属性可能对搜索结果有影响。基于Places documentation,它可以受到谷歌指数、全球受欢迎程度等因素的影响。
对于距离,现在需要可选属性,如keyword
、name
和types
。
希望这能澄清一些关于你的问题的观点。
https://stackoverflow.com/questions/34425910
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