blocks|key|1132251|text|我不确定Ruby中的语法，但是正则表达式应该是"(\d%2B)“，意思是一串大小为1或更大的数字。你可以在这里尝试一下：http://www.rubular.com/|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1132252|更新：我相信语法是/(\d%2B)/.match(your_string)|style|BOLD|1132253|entityMap|0|LINK|mutability|MUTABLE|url|http://www.rubular.com/^0|1M|N|0|0|0|3|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@$A|Q|B|R|1|S]]|C|$]]|$1|D|3|E|5|6|7|T|8|@$A|U|B|V|F|G]]|9|@]|C|$]]|$1|H|3|-4|5|6|7|W|8|@]|9|@]|C|$]]]|I|$J|$5|K|L|M|C|$N|O]]]]

I'm not sure on the syntax in Ruby, but the regular expression would be "(\d+)" meaning a string of digits of size 1 or more. You can try it out here: <a href="http://www.rubular.com/" rel="nofollow noreferrer">http://www.rubular.com/</a>

Updated:
I believe the syntax is /(\d+)/.match(your_string)

blocks|key|3752663|text|>+foo+=+"Search+result:16143+Results+found"
=>+"Search+result:16143+Results+found"
>+foo[/\d%2B/].to_i
=>+16143|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3752664|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>&gt; foo = "Search result:16143 Results found"
=&gt; "Search result:16143 Results found"
&gt; foo[/\d+/].to_i
=&gt; 16143
</code></pre>

blocks|key|3752558|text|这个正则表达式应该可以做到这一点：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3752559|\d%2B|code-block|syntax|javascript|3752560|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This regular expression should do it:

<pre><code>\d+
</code></pre>

blocks|key|532401|text|对于非正则表达式方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|532402|irb(main):001:0>+foo+=+"Search+result:16143+Results+found"
=>+"Search+result:16143+Results+found"
irb(main):002:0>+foo[foo.rindex(':')%2B1..foo.rindex('+Results')-1]
=>+"16143"|code-block|syntax|javascript|532403|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

For a non regular-expression approach:

<pre><code>irb(main):001:0&gt; foo = "Search result:16143 Results found"
=&gt; "Search result:16143 Results found"
irb(main):002:0&gt; foo[foo.rindex(':')+1..foo.rindex(' Results')-1]
=&gt; "16143"
</code></pre>

blocks|key|3752660|text|+#+check+that+the+string+you+have+matches+a+regular+expression
+if+foo+=~+/Search+result:(\d%2B)+Results+found/
+++#+the+first+parenthesized+term+is+put+in+$1
+++num_str+=+$1
+++puts+"I+found+#{num_str}!"
+++#+if+you+want+to+use+the+match+as+an+integer,+remember+to+use+#to_i+first
+++puts+"One+more+would+be+#{num_str.to_i+%2B+1}!"
+end|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3752661|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code> # check that the string you have matches a regular expression
 if foo =~ /Search result:(\d+) Results found/
 # the first parenthesized term is put in $1
 num_str = $1
 puts "I found #{num_str}!"
 # if you want to use the match as an integer, remember to use #to_i first
 puts "One more would be #{num_str.to_i + 1}!"
 end
</code></pre>

blocks|key|1132271|text|>+foo+=+"Search+result:16143+Results+found"
=>+"Search+result:16143+Results+found"
>+foo.scan(/\d/).to_i
=>+16143|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1132272|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>&gt; foo = "Search result:16143 Results found"
=&gt; "Search result:16143 Results found"
&gt; foo.scan(/\d/).to_i
=&gt; 16143
</code></pre>

I have a string "Search result:16143 Results found", and I need to retrieve 16143 out of it.

I am coding in ruby and I know this would be clean to get it using RegEx (as oppose to splitting string based on delimiters)

How would I retrieve the number from this string in ruby?

Retrieve number from the string pattern using regular expression

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个字符串"Search result:16143 Results found"，我需要从中检索16143个结果。我正在用ruby编写代码，我知道使用RegEx (相对于基于分隔符拆分字符串)来获得它会很干净。如何在ruby中从这个字符串中检索数字？

问使用正则表达式从字符串模式中检索数字
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回答 6

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