问Hibernate集合映射
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Stack Overflow用户

提问于 2012-05-18 20:31:49

回答 1查看 2.8K关注 0票数 0

我对Hibernate集合映射不太了解。尝试在Eclipse Hibernate透视图中添加持久性配置时会抛出以下错误：

Invalid ORM mapping file.
Error parsing XML (line14 : column 16): The content of element type "list" must match "(meta*,subselect?,cache?,synchronize*,comment?,key,(index|list-index),(element|one-to-many|many-to-many|composite-element|many-to-any),loader?,sql-insert?,sql-update?,sql-delete?,sql-delete-all?,filter*)".
Error parsing XML (line17 : column 15): The content of element type "map" must match "(meta*,subselect?,cache?,synchronize*,comment?,key,(map-key|composite-map-key|map-key-many-to-many|index|composite-index|index-many-to-many|index-many-to-any),(element|one-to-many|many-to-many|composite-element|many-to-any),loader?,sql-insert?,sql-update?,sql-delete?,sql-delete-all?,filter*)".

实际映射配置如下：

<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">

<hibernate-mapping>
    <class name="core.Server" table="server" schema="imdb">
        <id name="serverId" type="java.lang.Integer">
            <column name="SERVER_ID" />
            <generator class="identity" />
        </id>   
        <list name="sessions" inverse="true">
            <key column="serverID" not-null="true"/>
            <list-index column="SERVER_SESSION_NUMBER" />           
            <one-to-many class="core.Session"/>
        </list> 
        <map name="users" inverse="true">
            <key column="serverID" not-null="true"/>
            <map-key type="string" column="SERVER_USER_NUMBER"/>
            <one-to-many class="core.User"/>
        </map>  
    </class>
</hibernate-mapping>

<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">

<hibernate-mapping>
    <class name="core.User" table="user" schema="imdb">
        <id name="userId" type="java.lang.Integer">
            <column name="USER_ID" />
            <generator class="identity" />
        </id>   
        <property name="login" column="LOGIN" type="string" />          
        <property name="online" column="ONLINE" type="boolean" />   
        <property name="last_message" column="LAST_MESSAGE" type="string" />  
        <property name="newmessage" column="NEW_MESSAGE" type="boolean" />  
        <many-to-one name="serverID" column="SERVER_ID" class="core.Server"/>
        <list name="sessions" inverse="true">
            <key column="USER_ID" not-null="true"/>
            <one-to-many class="core.Session"/>
            <list-index column="USER_SESSION_NUMBER" />
        </list>     
    </class>
</hibernate-mapping>

<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">

<hibernate-mapping>
    <class name="core.Session" table="session" schema="imdb">
        <id name="sessionID" type="java.lang.Integer">
            <column name="SESSION_ID" />
            <generator class="identity" />
        </id>   
        <many-to-one name="serverID" column="SERVER_ID" class="core.Server"/>
        <many-to-one name="userID" column="USER_ID" class="core.User/>
    </class>
</hibernate-mapping>

感谢您的帮助！

hibernate

回答 1

Stack Overflow用户

回答已采纳

发布于 2012-05-18 20:48:09

顺序是特定的(并在错误消息中提供给您)。这不是hibernate的事情，而是XML模式的事情。

所以要保证标签的顺序是正确的，例如:需要在etc之前

编辑:不是所有的表都是错的。第一个是可以的。第二个有两个错误，应该是

<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">

<hibernate-mapping>
    <class name="core.User" table="user" schema="imdb">
        <id name="userId" type="java.lang.Integer">
            <column name="USER_ID" />
            <generator class="identity" />
        </id>   
        <property name="login" column="LOGIN" type="string" />          
        <property name="online" column="ONLINE" type="boolean" />   
        <property name="last_message" column="LAST_MESSAGE" type="string" />  
        <property name="newmessage" column="NEW_MESSAGE" type="boolean" />  
        <list name="sessions" inverse="true">
            <key column="USER_ID" not-null="true"/>
            <list-index column="USER_SESSION_NUMBER" />
            <one-to-many class="core.Session"/>          
        </list>   
        <many-to-one name="serverID" column="SERVER_ID" class="core.Server"/>
    </class>
</hibernate-mapping>

您的第三个是错误的，因为它在class="core.User“后面缺少一个引号，应该是

<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">

<hibernate-mapping>
    <class name="core.Session" table="session" schema="imdb">
        <id name="sessionID" type="java.lang.Integer">
            <column name="SESSION_ID" />
            <generator class="identity" />
        </id>   
        <many-to-one name="serverID" column="SERVER_ID" class="core.Server"/>
        <many-to-one name="userID" column="USER_ID" class="core.User"/>
     </class>
</hibernate-mapping>

票数 2

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原文链接：

https://stackoverflow.com/questions/10652717

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