问使用jQuery/JS上下切换DIV元素

EN

  <form name="f_form">
        Order name <input type="text" name="ord" id="order" />

        <div id="fields">
<div id="hid1"><a href="#" id="did1">
<img src="d.jpg" /></a><a href="#" id="uid1">
<img src="u.jpg" /></a><input type="text" name="p_name[]" id="names" />
<input type="text" name="quant[]" id="quant" size="3" />
<input type="text" name="pr[]" id="price" size="10" />
<input type="text" name="sum_a" id="sum" size="10" disabled="disabled"/>
        </div>
<input type="button" name="nauj" id="nau" value="Add item"/><br />
    </div>
    </form>

$("#nau").click(function () {
(newdiv = document.createElement('div')).id = "hid"+ (counter + 1) +"";
newdiv.innerHTML = '<a href="#" id="did'+ (counter + 1) +'"><img src="d.jpg" /></a><a href="#" id="uid'+ (counter + 1) +'"><img src="u.jpg" /></a><input type="text" name="p_name[]" id="names" />
<input type="text" name="quant[]" id="quant" size="3" />
<input type="text" name="pr[]" id="price" size="10" />
<input type="text" name="sum_a" id="sum" size="10" disabled="disabled"/><a href="#" id="delete'+ (counter + 1) +'">X</a>';
             document.getElementById('fields').appendChild(newdiv);
             counter++;
});

$("a[id^='uid']").on('click', function() {
            var numrow = $(this).attr("id");
            numrow = numrow.substr(3);
            var nr = 1;

            sumrow = numrow - nr;
            var eil = 'id=' + numrow;
            numrowas = "#hid"+numrow;
            srowas = "#hid"+sumrow;
                    $(numrowas).before($(srowas));
        });