使用这个json响应:
{
"self":"http://macpro.local:2990/jira/rest/api/2/issue/CSS-4/votes",
"votes":2,
"hasVoted":true,
"voters":[
{
"self":"http://macpro.local:2990/jira/rest/api/2/user?username=admin",
"name":"admin",
"avatarUrls":{
"16x16":"http://macpro.local:2990/jira/secure/useravatar?size=small&avatarId=10062",
"48x48":"http://macpro.local:2990/jira/secure/useravatar?avatarId=10062"
},
"displayName":"admin",
"active":true
},
{
"self":"http://macpro.local:2990/jira/rest/api/2/user?username=timn_1",
"name":"timn_1",
"avatarUrls":{
"16x16":"http://macpro.local:2990/jira/secure/useravatar?size=small&avatarId=10062",
"48x48":"http://macpro.local:2990/jira/secure/useravatar?avatarId=10062"
},
"displayName":"User Two",
"active":true
}
]
}我不知道如何从上面获取avatarUrls->16x16。我已经非常容易地使用如下命令获取其他所有内容:
$decoded = json_decode($result);
$decoded->votes; //returns # of votes
$decoded->voters->name; //returns the name但是我如何获得16x16的值呢?如果我尝试这样做,我会得到一个错误:
$decoded->voters->avatarUrls->16x16;发布于 2012-09-21 07:11:51
一如既往。
$decoded->voters->avatarUrls->{'16x16'}发布于 2012-09-21 07:14:02
你也可以这样做
$decoded = json_decode($result, true);
$decoded['voters']['avatarUrls']['16x16'];如果您更喜欢Array样式。
https://stackoverflow.com/questions/12522199
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