我有下表:
CREATE TABLE public.employees
(
employee_id integer NOT NULL,
name text NOT NULL,
date_of_birth date,
address text,
email text,
CONSTRAINT employees_pkey PRIMARY KEY (employees_id),
CONSTRAINT employees_email_key UNIQUE (email)
)如何在输出中列出每个员工的姓名和年龄?
谢谢。
发布于 2016-10-17 01:05:33
使用date_part()和age()函数
SELECT name text, date_part('year',age(date_of_birth)),* FROM public.employees有关日期函数https://www.postgresql.org/docs/current/static/functions-datetime.html的文档,请参见
发布于 2018-09-20 19:33:35
您可以像这样使用age()函数:
SELECT name, EXTRACT(year FROM age(current_date,date_of_birth)) :: int as age FROM public.employeeshttps://stackoverflow.com/questions/40072914
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