问按差异对列表元素进行分组

EN

int[] arr = {1,2,4,6,7,8,10,23,34,35,67,69,70};

for(int i=1, j=0; i<=arr.length; i++)
{
  if(i == arr.length || arr[i]-1 != arr[i-1])
  {
    System.out.printf("%s ", Arrays.toString(Arrays.copyOfRange(arr, j, i)));
    j = i;
  }
}

[1, 2] [4] [6, 7, 8] [10] [23] [34, 35] [67] [69, 70] 

array = [1,2,4,6,7,8,10,23,34,35,67,69,70]

last_index_before = array.size - 1
arr = []

# Can not use map because of the break maybe?
(0..last_index_before).each do |_|
  element = array.delete_at(0)
  break if element.nil? # We reached the end
  results = [element]

  next_element = array[0]
  while !next_element.nil? && (next_element - element) <= 1
    results << array.delete_at(0)
    element = next_element
    next_element = array[0]
  end
  arr << results
end

p arr

[[1, 2], [4], [6, 7, 8], [10], [23], [34, 35], [67], [69, 70]]