pygame主游戏函数在if语句后冻结
pygame主游戏函数在if语句后冻结
提问于 2020-10-17 02:31:52
正如标题中所说，在我选择一个按钮后，将代码移动到第二个if语句上，整个屏幕就会冻结并停止响应。我在努力寻找问题是什么，有什么洞察力可以导致冻结吗？我几乎可以肯定，问题不在于我没有包含的函数，因为它们都非常简单，不应该改变任何可能冻结代码的东西，尽管如果你认为它们可能是问题所在，我会在评论中添加它们。
def game():
player_health = 400
running = True
turn = 1
stopmusic()
pmusic("assets\\music\\battlemusic.mp3")
monster_health()
move_complete = False
monster_move = False
while player_health > 0:
if turn == 1:
while move_complete == False:
try:
screen.fill((0, 0, 0))
sewer = pygame.image.load('assets\\backgrounds\\sewer.png')
screen.blit(sewer,(0,0))
mx, my = pygame.mouse.get_pos()
mob()
button_attack = pygame.Rect(150, 500, 200, 50)
button_potion = pygame.Rect(150, 600, 200, 50)
button_spell = pygame.Rect(450, 500, 200, 50)
button_suicide = pygame.Rect(450, 600, 200, 50)
healthbar_outline = pygame.Rect(45,45, 1190, 60)
healthbar = pygame.Rect(50,50, (how_much_health_bar), 50)
combat_log = pygame.Rect(680, 150, 500, 450)
click = False
for event in pygame.event.get():
# this will make it so that you can press escape to exit this funciton
if event.type == QUIT:
pygame.quit()
sys.exit()
if event.type == KEYDOWN:
stopmusic()
pmusic("assets\\music\\backgroundmusic.mp3")
if event.key == K_ESCAPE:
running = False
if event.type == MOUSEBUTTONDOWN:
if event.button == 1:
click = True
if event.type == pygame.MOUSEBUTTONDOWN:
if event.button == 1:
if button_attack.collidepoint((mx, my)):
pygame.mixer.Sound.play(click_sound)
update_healthbar()
print(damage_done)
healthbar = pygame.Rect(50,50, (how_much_health_bar), 50)
move_complete = True
if button_potion.collidepoint((mx, my)):
if click:
pygame.mixer.Sound.play(click_sound)
if button_spell.collidepoint((mx, my)):
if click:
pygame.mixer.Sound.play(click_sound)
if button_suicide.collidepoint((mx, my)):
if click:
pygame.mixer.Sound.play(click_sound)
#this draws the boxs on the game window
pygame.draw.rect(screen, (0, 128, 128), healthbar_outline)
pygame.draw.rect(screen, (180, 0, 0), healthbar)
pygame.draw.rect(screen, (145, 39, 143), combat_log)
#this will show the monsters health total
pygame.draw.rect(screen, (255, 0, 0), healthbar)
if healthbar.collidepoint((mx, my)):
draw_text((display_health), font, (255, 255, 255), screen, 550, 60)
else:
pygame.draw.rect(screen, (255, 0, 0), healthbar)
if healthbar_outline.collidepoint((mx, my)):
pygame.draw.rect(screen, (255, 0, 0), healthbar)
draw_text((display_health), font, (255, 255, 255), screen, 550, 60)
else:
pygame.draw.rect(screen, (255, 0, 0), healthbar)
#this makes the buttons glow as you hover over them
if button_attack.collidepoint((mx, my)):
pygame.draw.rect(screen, (255, 0, 0), button_attack)
else:
pygame.draw.rect(screen, (180, 0, 0), button_attack)
draw_text('attack', font, (255, 255, 255), screen, 150, 500)
if button_potion.collidepoint((mx, my)):
pygame.draw.rect(screen, (255, 0, 0), button_potion)
else:
pygame.draw.rect(screen, (180, 0, 0), button_potion)
draw_text('potion', font, (255, 255, 255), screen, 150, 600)
if button_spell.collidepoint((mx, my)):
pygame.draw.rect(screen, (255, 0, 0), button_spell)
else:
pygame.draw.rect(screen, (180, 0, 0), button_spell)
draw_text('spell', font, (255, 255, 255), screen, 450, 500)
if button_suicide.collidepoint((mx, my)):
pygame.draw.rect(screen, (255, 0, 0), button_suicide)
else:
pygame.draw.rect(screen, (180, 0, 0), button_suicide)
draw_text('suicide', font, (255, 255, 255), screen, 450, 600)
turn = 2
print(turn)
pygame.display.update()
mainClock.tick(60)
except:
print("please just work")
if turn == 2:
try:
turn = 1
print(turn)
pygame.display.update()
mainClock.tick(60)
except:
print("please just work")回答 1
Stack Overflow用户
发布于 2020-10-17 02:40:07
窗口冻结是因为在第二种情况下没有事件循环。请分别查看pygame.event.get() pygame.event.pump()
对于游戏的每一帧，您将需要对事件队列进行某种调用。这确保了您的程序可以在内部与操作系统的其余部分进行交互。
在第二种情况下，实现与第一种情况类似的事件循环。例如：
for event in pygame.event.get():
# this will make it so that you can press escape to exit this funciton
if event.type == QUIT:
pygame.quit()
sys.exit()页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/64394605
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