问使用parser_args()向python中的请求添加参数时，烧瓶Restful - Status 400

EN

from flask import Flask
from flask_restful import Resource, Api, reqparse

app = Flask(__name__)
api = Api(app)

class Example(Resource):

    def get(self):
        parser = reqparse.RequestParser()
        parser.add_argument('some_arg')
        args = parser.parse_args()
        return {"Param Entered": args['some_arg']}

api.add_resource(Example, '/')

if __name__ == '__main__':
    app.run()

GET <my_url>/?some_arg=<some_text>