在第一次测试之后,Python似乎使用了与Linux排序(gnu )相同的排序顺序和C排序顺序(如果区域设置为"C")。
但是,我希望能够编写Python代码,根据区域设置,按照与gnu排序相同的方式进行排序和比较。
举例说明这个问题的小示例代码:
import os
import subprocess
words = [
"Abd",
"éfg",
"aBd",
"aBd",
"zzz",
"ZZZ",
"efg",
"abd",
"fff",
]
with open("tosort", "w") as fout:
for word in words:
fout.write(word + "\n")
os.environ["LC_ALL"] = "en_US.UTF-8"
proc = subprocess.Popen(["sort", "tosort"], stdout=subprocess.PIPE)
sort_en_utf = proc.stdout.read().decode('utf-8').split()
os.environ["LC_ALL"] = "C"
proc = subprocess.Popen(["sort", "tosort"], stdout=subprocess.PIPE)
sort_c = proc.stdout.read().decode('utf-8').split()
os.environ["LC_ALL"] = "en_US.UTF-8"
sort_py = sorted(words)
for row in zip(sort_en_utf, sort_c, sort_py):
print(" ".join(row))如果运行上述代码,我将得到以下输出:
abd Abd Abd
aBd ZZZ ZZZ
aBd aBd aBd
Abd aBd aBd
efg abd abd
éfg efg efg
fff fff fff
zzz zzz zzz
ZZZ éfg éfg如果区域设置为"en_US.UTF-8“列2和3,则第1列是我希望在python代码中具有的排序/比较顺序,如果区域设置为"C”,该python排序方式与linux的排序相同。
所以我也想知道是否有一种方法:
"éfg" < "fff"产率真。我不坚持一个比较操作符,我也可以调用一个函数。但是排序结果应该考虑当前的区域设置。
发布于 2019-10-01 23:15:49
嗯,不知怎么我忽略了这一点:
python https://docs.python.org/3.5/howto/sorting.html的排序文档在最后一节中提到了函数locale.strxfrm() (参见https://docs.python.org/3.5/library/locale.html#locale.strxfrm )作为排序的关键函数,locale.strcoll()作为比较函数。
因此,修改后的代码几乎没有问题,只是比较函数不直接返回true / false,但在我的上下文中是可以的。
import subprocess
words = [
"Abd",
"éfg",
"aBd",
"aBd",
"zzz",
"ZZZ",
"efg",
"abd",
"fff",
"sra",
"ssa",
"ssb",
"stb",
"ßaa",
]
val1 = "ßaa"
val2 = "ssb"
with open("tosort", "w") as fout:
for word in words:
fout.write(word + "\n")
os.environ["LC_ALL"] = "en_US.UTF-8"
proc = subprocess.Popen(["sort", "tosort"], stdout=subprocess.PIPE)
sort_en_utf = proc.stdout.read().decode('utf-8').split()
os.environ["LC_ALL"] = "C"
proc = subprocess.Popen(["sort", "tosort"], stdout=subprocess.PIPE)
sort_c = proc.stdout.read().decode('utf-8').split()
locale.setlocale(locale.LC_ALL, "en_US.UTF-8")
sort_py1 = sorted(words, key=lambda v: locale.strxfrm(v))
print("%r < %r = %s , but locale.strcoll(%r, %r) = %s for %s"
% (val1, val2, val1 < val2, val1, val2,
locale.strcoll(val1, val2), locale.getlocale())
)
locale.setlocale(locale.LC_ALL, "C")
sort_py2 = sorted(words, key=lambda v: locale.strxfrm(v))
print("%r < %r = %s , but locale.strcoll(%r, %r) = %s for %s"
% (val1, val2, val1 < val2, val1, val2,
locale.strcoll(val1, val2), locale.getlocale())
)
for row in zip(sort_en_utf, sort_py1, sort_c, sort_py2):
print(" ".join(row))输出将是
'ßaa' < 'ssb' = False , but locale.strcoll('ßaa', 'ssb') = -1 for ('en_US', 'UTF-8')
'ßaa' < 'ssb' = False , but locale.strcoll('ßaa', 'ssb') = 1 for (None, None)
abd abd Abd Abd
aBd aBd ZZZ ZZZ
aBd aBd aBd aBd
Abd Abd aBd aBd
efg efg abd abd
éfg éfg efg efg
fff fff fff fff
sra sra sra sra
ssa ssa ssa ssa
ßaa ßaa ssb ssb
ssb ssb stb stb
stb stb zzz zzz
zzz zzz ßaa ßaa
ZZZ ZZZ éfg éfghttps://stackoverflow.com/questions/58192898
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