大家好,我开始学习编码和第二语言英语。我有一个小项目,我使用Arduino 、esp8266、dht11、lcd I2C,在我的项目中使用blynk< code >E 29应用程序,但我想知道如何在不打开WiFi的情况下从E 110
dhtE 211到E 112
lcd<>E 213/code>获取信息数据。现在我得到的信息(温度和湿度)在液晶显示时,只有WiFi。如何使温度和湿度显示在液晶显示器上,有和没有WiFi。
#define BLYNK_PRINT Serial
#include <ESP8266_Lib.h>
#include <BlynkSimpleShieldEsp8266.h>
#include <DHT.h>
#include <Wire.h>
#include <LiquidCrystal_I2C.h>
LiquidCrystal_I2C lcd(0x27,20,4);
char auth[] = "xxxxxxxxxxxxxxxxxxxxxxxxxxxxx";
char ssid[] = "xxxxxxxxxxxx";
char pass[] = "xxxxxxxxxxxxxx";
#include <SoftwareSerial.h>
SoftwareSerial EspSerial(2, 3); // TX, RX
#define ESP8266_BAUD 9600
ESP8266 wifi(&EspSerial);
#define DHTPIN 8
#define DHTTYPE DHT11
DHT dht(DHTPIN, DHTTYPE);
BlynkTimer timer;
void setup()
{
Serial.begin(115200);
lcd.init();
lcd.backlight();
lcd.clear();
dht.begin();
EspSerial.begin(ESP8266_BAUD);
delay(10);
Blynk.begin(auth, wifi, ssid, pass);
dht.begin();
timer.setInterval(1000L, sendSensor);
}
void loop()
{
Blynk.run();
timer.run();
}
void sendSensor()
{
float h = dht.readHumidity();
float t = dht.readTemperature();
lcd.backlight();
lcd.setCursor(0,0);
lcd.print("Humidity: ");
lcd.print(h);
lcd.print(" %");
lcd.setCursor(0,2);
lcd.print("Temperature: ");
lcd.print(t);
lcd.print(" C ");
Serial.print("Humidity: ");
Serial.print(h);
Serial.println (" % ");
Serial.print("Temperature: ");
Serial.print(t);
Serial.println (" C ");
if (isnan(h) || isnan(t)) {
lcd.backlight();
lcd.setCursor(0,0);
lcd.print("Temperature: ");
lcd.print(t);
lcd.print(" C ");
lcd.setCursor(0,2);
lcd.print("Humidity: ");
lcd.print(h);
lcd.print(" % ");
Serial.print("Humidity: ");
Serial.print(h);
Serial.println (" % ");
Serial.print("Temperature: ");
Serial.print(t);
Serial.println (" C ");
}
Blynk.virtualWrite(V6, h);
Blynk.virtualWrite(V2, t);
Serial.print("Humidity: ");
Serial.print(h);
Serial.println (" % ");
Serial.print("Temperature: ");
Serial.print(t);
Serial.println (" C ");
}
发布于 2020-07-18 04:11:07
如果您没有连接wifi模块或您的模块无法连接,则您的Blynk.begin(auth、wifi、ssid、pass);函数应该已经无法执行。
确保只有当设备响应时,才执行将数据传递给另一个设备的代码的每个部分。尝试从以下位置捕捉缺少的连接:
if (!Blynk.connected()){
do someting....
}
https://stackoverflow.com/questions/62967837
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