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社区首页 >问答首页 >看门狗兼容性:"CancelIoEx“的解决方案

看门狗兼容性:"CancelIoEx“的解决方案
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Stack Overflow用户
提问于 2014-09-04 15:15:20
回答 1查看 1.3K关注 0票数 1

使用python 看门狗文件系统事件监视库,我注意到在Windows 2003下使用时,它进入了“轮询模式”,从而停止使用异步OS通知,因此,在大量文件更改的情况下,严重降低了系统性能。

我将问题追溯到watchdog/observers/winapi.py文件,其中使用了CancelIoEx系统调用,以便在用户希望停止监视监视的目录或文件时停止ReadDirectoryChangesW调用锁:

(winapi.py)

代码语言:javascript
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CancelIoEx = ctypes.windll.kernel32.CancelIoEx
CancelIoEx.restype = ctypes.wintypes.BOOL
CancelIoEx.errcheck = _errcheck_bool
CancelIoEx.argtypes = (
    ctypes.wintypes.HANDLE,  # hObject
    ctypes.POINTER(OVERLAPPED)  # lpOverlapped
)

...
...
...

def close_directory_handle(handle):
    try:
        CancelIoEx(handle, None)  # force ReadDirectoryChangesW to return
    except WindowsError:
        return

CancelIoEx调用的问题是直到Windows 2008:http://msdn.microsoft.com/en-us/library/windows/desktop/aa363792(v=vs.85).aspx才可用

一种可能的选择是更改close_directory_handle,使其在受监视的目录中创建一个模拟文件,从而打开等待ReadDirectoryChangesW返回的线程。

但是,我注意到Windows 2003中的CancelIo系统调用是事实上是可用的

取消由调用线程为指定文件发出的所有挂起的输入和输出(I/O)操作。该函数不会取消其他线程为文件句柄发出的I/O操作。要取消来自另一个线程的I/O操作,请使用CancelIoEx函数。

但是调用CancelIo不会影响等待线程。

你知道如何解决这个问题吗?可以使用threading.enumerate(),发出一个信号,由每个被这些处理程序调用的CancelIo处理的线程处理?

EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2014-09-15 07:47:04

自然的方法是实现一个完成例程,并使用其重叠模式调用ReadDirectoryChangesW。下面的示例演示了实现此操作的方法:

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RDCW_CALLBACK_F = ctypes.WINFUNCTYPE(None, ctypes.wintypes.DWORD, ctypes.wintypes.DWORD, ctypes.POINTER(OVERLAPPED))

首先,创建一个WINFUNCTYPE工厂,它将用于从python方法生成类似于C的函数(可从Windows调用)。在这种情况下,没有返回值和对应于

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VOID CALLBACK FileIOCompletionRoutine(
  _In_     DWORD dwErrorCode,
  _In_     DWORD dwNumberOfBytesTransfered,
  _Inout_  LPOVERLAPPED lpOverlapped
);

FileIOCompletionRoutine标头

回调引用和重叠结构需要添加到ReadDirectoryChangesW参数列表中:

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ReadDirectoryChangesW = ctypes.windll.kernel32.ReadDirectoryChangesW

ReadDirectoryChangesW.restype = ctypes.wintypes.BOOL
ReadDirectoryChangesW.errcheck = _errcheck_bool
ReadDirectoryChangesW.argtypes = (
    ctypes.wintypes.HANDLE,  # hDirectory
    LPVOID,  # lpBuffer
    ctypes.wintypes.DWORD,  # nBufferLength
    ctypes.wintypes.BOOL,  # bWatchSubtree
    ctypes.wintypes.DWORD,  # dwNotifyFilter
    ctypes.POINTER(ctypes.wintypes.DWORD),  # lpBytesReturned
    ctypes.POINTER(OVERLAPPED),  # lpOverlapped
    RDCW_CALLBACK_F  # FileIOCompletionRoutine # lpCompletionRoutine
)

从这里开始,我们准备执行重叠的系统调用。这是一个简单的调用-- bacl只是用来测试一切是否正常:

代码语言:javascript
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def dir_change_callback(dwErrorCode,dwNumberOfBytesTransfered,p):
     print("dir_change_callback! PID:" + str(os.getpid()))
     print("CALLBACK THREAD: " + str(threading.currentThread()))

准备并执行呼叫:

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event_buffer = ctypes.create_string_buffer(BUFFER_SIZE)
nbytes = ctypes.wintypes.DWORD()
overlapped_read_dir = OVERLAPPED()
call2pass = RDCW_CALLBACK_F(dir_change_callback)

hand = get_directory_handle(os.path.abspath("/test/"))

def docall():
    ReadDirectoryChangesW(hand, ctypes.byref(event_buffer),
                          len(event_buffer), False,
                          WATCHDOG_FILE_NOTIFY_FLAGS,
                          ctypes.byref(nbytes), 
                          ctypes.byref(overlapped_read_dir), call2pass)

print("Waiting!")
docall()

如果将所有这些代码加载并执行到DreamPie交互式shell中,则可以检查系统调用是否完成,回调是否执行,从而在c:\test目录下完成第一次更改后打印线程和pid编号。此外,您还会注意到它们与主线程和进程相同:尽管事件是由分离的线程引发的,回调运行在与我们的主程序相同的进程和线程中,从而提供了一种不想要的行为:

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lck = threading.Lock()

def dir_change_callback(dwErrorCode,dwNumberOfBytesTransfered,p):
     print("dir_change_callback! PID:" + str(os.getpid()))
     print("CALLBACK THREAD: " + str(threading.currentThread()))

...
...
...

lck.acquire()
print("Waiting!")
docall()
lck.acquire()

此程序将锁定主线程,回调将永远不会执行。我尝试了许多同步工具,甚至Windows信号量总是具有相同的行为,因此,最后,我决定在使用ReadDirectoryChangesW库管理和同步的单独进程中使用multiprocessing的同步配置来实现异步调用:

get_directory_handle的调用不会返回由windows提供的句柄号,而是返回一个由winapi库管理的句柄号,为此,我实现了句柄生成器:

代码语言:javascript
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class FakeHandleFactory():
    _hl = threading.Lock()
    _next = 0
    @staticmethod
    def next():
        FakeHandleFactory._hl.acquire()
        ret = FakeHandleFactory._next
        FakeHandleFactory._next += 1
        FakeHandleFactory._hl.release()
        return ret

每个生成的句柄必须与文件系统路径全局关联:

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handle2file = {}

现在,每次对read_directory_changes的调用都将生成ReadDirectoryRequest (从multiprocessing.Process派生)对象:

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class ReadDirectoryRequest(multiprocessing.Process):

    def _perform_and_wait4request(self, path, recursive, event_buffer, nbytes):
        hdl = CreateFileW(path, FILE_LIST_DIRECTORY, WATCHDOG_FILE_SHARE_FLAGS,
                       None, OPEN_EXISTING, WATCHDOG_FILE_FLAGS, None)
        #print("path: " + path)
        aux_buffer = ctypes.create_string_buffer(BUFFER_SIZE)
        aux_n = ctypes.wintypes.DWORD()
        #print("_perform_and_wait4request! PID:" + str(os.getpid()))
        #print("CALLBACK THREAD: " + str(threading.currentThread()) + "\n----------")
        try:
            ReadDirectoryChangesW(hdl, ctypes.byref(aux_buffer),
                              len(event_buffer), recursive,
                              WATCHDOG_FILE_NOTIFY_FLAGS,
                              ctypes.byref(aux_n), None, None)
        except WindowsError as e:
            print("!" + str(e))
            if e.winerror == ERROR_OPERATION_ABORTED:
                nbytes = 0
                event_buffer = []
            else:
                nbytes = 0
                event_buffer = []
        # Python 2/3 compat
        nbytes.value = aux_n.value
        for i in xrange(self.int_class(aux_n.value)):
            event_buffer[i] = aux_buffer[i]
        CloseHandle(hdl)
        try:
            self.lck.release()
        except:
            pass



    def __init__(self, handle, recursive):
        buffer = ctypes.create_string_buffer(BUFFER_SIZE)
        self.event_buffer = multiprocessing.Array(ctypes.c_char, buffer)
        self.nbytes = multiprocessing.Value(ctypes.wintypes.DWORD, 0)
        targetPath = handle2file.get(handle, None)
        super(ReadDirectoryRequest, self).__init__(target=self._perform_and_wait4request, args=(targetPath, recursive, self.event_buffer, self.nbytes))
        self.daemon = True
        self.lck = multiprocessing.Lock()
        self.result = None
        try:
            self.int_class = long
        except NameError:
            self.int_class = int
        if targetPath is None:
            self.result = ([], -1)

    def CancelIo(self):
        try:
            self.result = ([], 0)
            self.lck.release()
        except:
            pass

    def read_changes(self):
        #print("read_changes! PID:" + str(os.getpid()))
        #print("CALLBACK THREAD: " + str(threading.currentThread()) + "\n----------")
        if self.result is not None:
            raise Exception("ReadDirectoryRequest object can be used only once!")
        self.lck.acquire()
        self.start()
        self.lck.acquire()
        self.result = (self.event_buffer, self.int_class(self.nbytes.value))
        return self.result

该类指定Process,提供执行系统调用并等待(或)的进程:

  • 已引发更改事件。
  • 主线程通过调用ReadDirectoryRequest对象CancelIo方法来取消请求。

请注意:

  • get_directory_handle
  • close_directory_handle
  • read_directory_changes

角色现在负责管理请求。为此,需要线程锁和辅助数据结构:

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rqIndexLck = threading.Lock() # Protects the access to `rqIndex`
rqIndex = {} # Maps handles to request objects sets.

get_directory_handle

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def get_directory_handle(path):
    rqIndexLck.acquire()
    ret = FakeHandleFactory.next()
    handle2file[ret] = path
    rqIndexLck.release()
    return ret

close_directory_handle

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def close_directory_handle(handle):
    rqIndexLck.acquire()
    rqset4handle = rqIndex.get(handle, None)
    if rqset4handle is not None:
        for rq in rqset4handle:
            rq.CancelIo()
        del rqIndex[handle]
    if handle in handle2file:
        del handle2file[handle]
    rqIndexLck.release()

最后但并非最不重要的是:read_directory_changes

代码语言:javascript
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def read_directory_changes(handle, recursive):
    rqIndexLck.acquire()
    rq = ReadDirectoryRequest(handle, recursive)
    set4handle = None
    if handle in rqIndex:
        set4handle = rqIndex[handle]
    else:
        set4handle = set()
        rqIndex[handle] = set4handle
    set4handle.add(rq)
    rqIndexLck.release()
    ret = rq.read_changes()
    rqIndexLck.acquire()
    if rq in set4handle:
        set4handle.remove(rq)
    rqIndexLck.release()
    return ret
票数 1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/25669139

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