我正在学习“编程集体智慧”一书。下面是我的代码:
import feedparser
import re
# Returns title and dictionary of word counts for an RSS feed
def getwordcounts(url):
# Parse the feed
d = feedparser.parse(url)
wc={}
# Loop over all the entries
for e in d.entries:
if 'summary' in e:
summary = e.summary
else:
summary = e.description
# Extract a list of words
words = getwords(e.title + '' + summary)
for word in words:
wc.setdefault(word, 0)
wc[word] += 1
return d.feed.title, wc
def getwords(html):
# Remove all the HTML tags
txt = re.compile(r'[^>]+>').sub('',html)
# Split words by all non-alpha characters
words = re.compile(r'[^A-Z^a-z]+').split(txt)
# Convert to lowercase
return [word.lower() for word in words if word!='']
apcount = {}
wordcounts = {}
for feedurl in file('feedlist.txt'):
title, wc = getwordcounts(feedurl)
wordcounts[title] = wc
for word, count in wc.items():
apcount.setdefault(word, 0)
if count>1:
apcount[word] += 1
wordlist = []
for w, bc in apcount.items():
frac = float(bc)/len(feedlist)
if frac>0.1 and frac<0.5:
wordlist.append(w)
out = file('blogdata.txt', 'w')
out.write('Blog')
for word in wordlist:
out.write('\t%s' % word)
out.write('\n')
for blog, wc in wordcounts.items():
out.write(blog)
for word in wordlist:
if word in wc:
out.wirte('\t%d' % wc[word])
else:
out.write('\t0')
out.write('\n')
当我运行这个脚本时,我收到了这样的消息:
Traceback (most recent call last):
File "generatefeedvector.py", line 38, in <module>
title, wc = getwordcounts(feedurl)
File "generatefeedvector.py", line 22, in getwordcounts
return d.feed.title, wc
File "build/bdist.linux-x86_64/egg/feedparser.py", line 416, in __getattr__
AttributeError: object has no attribute 'title'
我已经检查了have解析器的版本是5.1.3。
那么如何解决这个问题呢?谢谢
发布于 2015-03-15 18:02:46
您试图用feedparser
解析的URL不是一个有效的提要(用feedvalidator
检查它),而是一个网页,或者提要是空的,或者是title
是空的。
作为解决办法,请使用getattr()
return getattr(d.feed, 'title', 'Unknown title'), wc
另见:
https://stackoverflow.com/questions/29068485
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