我需要设计一个没有重复组的表,我认为我已经这样做了,但是这个表看起来与它们的链接方式是正确的吗?或者有什么我可以改进的?我运行了所有的查询,我有几个重复的小组球员和经理,因为我把他们都放在一个班组,所以我把他们分成team_player和team_manager,这样一个或多个经理也可以管理一个团队,反之亦然,体育场等。
drop table film_director;
drop table film_actor;
drop table film;
drop table studio;
drop table actor;
drop table director;
CREATE TABLE studio(
studio_ID NUMBER NOT NULL,
studio_Name VARCHAR2(30),
PRIMARY KEY(studio_ID));
CREATE TABLE film(
film_ID NUMBER NOT NULL,
studio_ID NUMBER NOT NULL,
genre VARCHAR2(30),
genre_ID NUMBER(1),
film_Len NUMBER(3),
film_Title VARCHAR2(30) NOT NULL,
year_Released NUMBER NOT NULL,
PRIMARY KEY(film_ID),
FOREIGN KEY (studio_ID) REFERENCES studio);
CREATE TABLE director(
director_ID NUMBER NOT NULL,
director_fname VARCHAR2(30),
director_lname VARCHAR2(30),
PRIMARY KEY(director_ID));
CREATE TABLE actor(
actor_ID NUMBER NOT NULL,
actor_fname VARCHAR2(15),
actor_lname VARCHAR2(15),
PRIMARY KEY(actor_ID));
CREATE TABLE film_actor(
film_ID NUMBER NOT NULL,
actor_ID NUMBER NOT NULL,
PRIMARY KEY(film_ID, actor_ID),
FOREIGN KEY(film_ID) REFERENCES film(film_ID),
FOREIGN KEY(actor_ID) REFERENCES actor(actor_ID));
CREATE TABLE film_director(
film_ID NUMBER NOT NULL,
director_ID NUMBER NOT NULL,
PRIMARY KEY(film_ID, director_ID),
FOREIGN KEY(film_ID) REFERENCES film(film_ID),
FOREIGN KEY(director_ID) REFERENCES director(director_ID));
INSERT INTO studio (studio_ID, studio_Name) VALUES (1, 'Paramount');
INSERT INTO studio (studio_ID, studio_Name) VALUES (2, 'Warner Bros');
INSERT INTO studio (studio_ID, studio_Name) VALUES (3, 'Film4');
INSERT INTO studio (studio_ID, studio_Name) VALUES (4, 'Working Title Films');
INSERT INTO film (film_ID, studio_ID, genre, genre_ID, film_Len, film_Title, year_Released) VALUES (1, 1, 'Comedy', 1, 180, 'The Wolf Of Wall Street', 2013);
INSERT INTO film (film_ID, studio_ID, genre, genre_ID, film_Len, film_Title, year_Released) VALUES (2, 2, 'Romance', 2, 143, 'The Great Gatsby', 2013);
INSERT INTO film (film_ID, studio_ID, genre, genre_ID, film_Len, film_Title, year_Released) VALUES (3, 3, 'Science Fiction', 3, 103, 'Never Let Me Go', 2008);
INSERT INTO film (film_ID, studio_ID, genre, genre_ID, film_Len, film_Title, year_Released) VALUES (4, 4, 'Romance', 4, 127, 'Pride and Prejudice', 2005);
INSERT INTO director (director_ID, director_fname, director_lname) VALUES (1, 'Martin', 'Scorcese');
INSERT INTO director (director_ID, director_fname, director_lname) VALUES (2, 'Baz', 'Luhrmann');
INSERT INTO director (director_ID, director_fname, director_lname) VALUES (3, 'Mark', 'Romanek');
INSERT INTO director (director_ID, director_fname, director_lname) VALUES (4, 'Joe', 'Wright');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (1, 'Matthew', 'McConnaughy');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (2, 'Leonardo', 'DiCaprio');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (3, 'Margot', 'Robbie');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (4, 'Joanna', 'Lumley');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (5, 'Carey', 'Mulligan');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (6, 'Tobey', 'Maguire');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (7, 'Joel', 'Edgerton');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (8, 'Keira', 'Knightly');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (9, 'Andrew', 'Garfield');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (10, 'Sally', 'Hawkins');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (11, 'Judi', 'Dench');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (12, 'Matthew', 'Macfadyen');
INSERT INTO film_actor (film_ID, actor_ID) VALUES (1, 1);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (1, 2);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (1, 3);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (1, 4);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (2, 2);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (2, 5);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (2, 6);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (2, 7);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (3, 5);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (3, 8);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (3, 9);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (3, 10);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (4, 5);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (4, 8);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (4, 11);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (4, 12);
INSERT INTO film_director (film_ID, director_ID) VALUES (1,1);
INSERT INTO film_director (film_ID, director_ID) VALUES (2,2);
INSERT INTO film_director (film_ID, director_ID) VALUES (3,3);
INSERT INTO film_director (film_ID, director_ID) VALUES (4,4);
发布于 2016-04-08 11:25:47
我同意sdmon --因为导演和演员都有相同的属性,所以把它们都放在一个表中,并在“事实”表中指定他们的角色是有意义的。
一部电影能有一个以上的导演吗?如果不需要,则不需要film_director表,只需在电影表中为“导演”提供一列。否则,您确实需要film_director表。
一部电影能被绑在一个以上的制片厂吗?在您的模型中,您的胶片表中有一个用于studio_id的列,但也有一个film_studio表。你不需要两者兼得。如果电影总是由单个工作室制作,则需要列(而不是表)。如果您需要为一部电影放映多个工作室,那么您需要额外的表,而不是列。
其他一切看起来都很好。祝好运!
发布于 2016-04-08 10:18:00
我只有一张供用户使用的桌子(导演/演员),因为如果导演也是昆汀·塔伦蒂诺()这样的演员,他的大部分电影都会出现。你必须重复数据。
试着把你的模型提高到BCNF或4NF,你就会没事的
https://stackoverflow.com/questions/36506433
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