JAX-RS在REST中的错误处理
JAX-RS在REST中的错误处理
提问于 2016-08-16 09:46:20
的任务：不是在我的堆栈跟踪中接收通用的HTTP 500 Internal Server Error，而是在客户端看到相同的可怕的堆栈跟踪，我希望看到我用另一个状态代码(例如403)定制的消息，对于开发人员来说，这将更加清晰，已经发生了什么。并向用户添加一些有关异常的消息。
下面是我的应用程序中更改的几个类：
服务器部分：
AppException.class -所有我的服务器响应异常(在返回给客户端之前)，我想转换成这个异常。类标准实体类
public class AppException extends WebApplicationException {
Integer status;
/** application specific error code */
int code;
/** link documenting the exception */
String link;
/** detailed error description for developers */
String developerMessage;
public AppException(int status, int code, String message, String developerMessage, String link) {
super(message);
this.status = status;
this.code = code;
this.developerMessage = developerMessage;
this.link = link;
}
public int getStatus() {
return status;
}
public void setStatus(int status) {
this.status = status;
}
public int getCode() {
return code;
}
public void setCode(int code) {
this.code = code;
}
public String getDeveloperMessage() {
return developerMessage;
}
public void setDeveloperMessage(String developerMessage) {
this.developerMessage = developerMessage;
}
public String getLink() {
return link;
}
public void setLink(String link) {
this.link = link;
}
public AppException() {
}
public AppException(String message) {
super("Something went wrong on the server");
}
}客户端接收ÀppExceptionMapper.class - AppException到JAX运行时，而不是标准异常.
@Provider
public class AppExceptionMapper implements ExceptionMapper<AppException> {
@Override
public Response toResponse(AppException exception) {
return Response.status(403)
.entity("toResponse entity").type("text/plain").build();
}
}ApplicationService.class-抛出AppException的服务类
@Path("/applications")
@Produces(MediaType.APPLICATION_JSON)
@Consumes(MediaType.APPLICATION_JSON)
public interface ApplicationService {
@DELETE
@Path("/deleteById")
void deleteById(@NotNull Long id) throws AppException;
}客户端部分：
ErrorHandlingFilter.class-我的反应捕捉AppException。在这里，我希望根据状态将每个响应异常转换为另一个异常。
@Provider
public class ErrorHandlingFilter implements ClientResponseFilter {
private static ObjectMapper _MAPPER = new ObjectMapper();
@Override
public void filter(ClientRequestContext requestContext, ClientResponseContext responseContext) throws IOException {
if (responseContext.getStatus() != Response.Status.OK.getStatusCode()) {
if(responseContext.hasEntity()) {
Error error = _MAPPER.readValue(responseContext.getEntityStream(), Error.class);
String message = error.getMessage();
Response.Status status = Response.Status.fromStatusCode(responseContext.getStatus());
AppException clientException;
switch (status) {
case INTERNAL_SERVER_ERROR:
clientException = new PermissionException(message);
break;
case NOT_FOUND:
clientException = new MyNotFoundException(message);
break;
default:
clientException = new WhatEverException(message);
}
throw clientException;
}
}
}
}PermissionException.class -我想要转换AppException的异常，如果它附带了500个状态代码。
public class PermissionException extends AppException{
public PermissionException(String message) {
super("403 - Forbidden. You dont have enough rights to delete this Application");
}
Integer status;
/** application specific error code */
int code;
/** link documenting the exception */
String link;
/** detailed error description for developers */
String developerMessage;
public PermissionException(int status, int code, String message, String developerMessage, String link) {
super(message);
this.status = status;
this.code = code;
this.developerMessage = developerMessage;
this.link = link;
}
public int getStatus() {
return status;
}
public void setStatus(int status) {
this.status = status;
}
public int getCode() {
return code;
}
public void setCode(int code) {
this.code = code;
}
public String getDeveloperMessage() {
return developerMessage;
}
public void setDeveloperMessage(String developerMessage) {
this.developerMessage = developerMessage;
}
public String getLink() {
return link;
}
public void setLink(String link) {
this.link = link;
}
public PermissionException() {}
}ApplicationPresenter.class- - UI逻辑的一部分，在这里，我希望与ErrorHandlingFilter抛出的PermissionException有关。
@SpringPresenter
public class ApplicationPresenter implements ApplicationView.Observer {
@Resource
private ApplicationService applicationService;
@Resource
private UiEnvironment uiEnvironment;
@Override
public void deleteSelectedApplication(BeanItemGrid<Application> applicationGrid) {
try {
applicationService.deleteById(applicationGrid.getSelectedItem().getId());
} catch (PermissionException e) {
e.printStackTrace();
e.getMessage();
} catch (AppException e2) {
}
}
}我该如何解决我的问题？我还在接受标准的500 InternalErrorException.
几乎再次更新了整个问题！
回答 5
Stack Overflow用户
发布于 2016-08-16 11:21:01
当您有一个ExceptionMapper时，您不会自己捕获异常，而是让框架在对HTTP调用资源方法时捕获它。
Stack Overflow用户
发布于 2016-08-19 10:43:27
执行错误处理的正确方法是注册ExceptionMapper实例，这些实例知道在发生特定(或一般)异常时应该返回什么响应。
@Provider
public class PermissionExceptionHandler implements ExceptionMapper<PermissionException>{
@Override
public Response toResponse(PermissionException ex){
//You can place whatever logic you need here
return Response.status(403).entity(yourMessage).build();
}
}请看我的另一个答案，以获得更多细节：https://stackoverflow.com/a/23858695/2588800
Stack Overflow用户
发布于 2016-08-25 12:40:58
这是一个泽西实例，但是您可以从这里中提取所需的信息。最后，我只会抛出一个异常，并将此异常映射到任何想要的响应。
让我们假设您有以下ressource方法，发现了异常：
@Path("items/{itemid}/")
public Item getItem(@PathParam("itemid") String itemid) {
Item i = getItems().get(itemid);
if (i == null) {
throw new CustomNotFoundException("Item, " + itemid + ", is not found");
}
return i;
}创建异常类：
public class CustomNotFoundException extends WebApplicationException {
/**
* Create a HTTP 404 (Not Found) exception.
*/
public CustomNotFoundException() {
super(Responses.notFound().build());
}
/**
* Create a HTTP 404 (Not Found) exception.
* @param message the String that is the entity of the 404 response.
*/
public CustomNotFoundException(String message) {
super(Response.status(Responses.NOT_FOUND).
entity(message).type("text/plain").build());
}
}现在添加异常映射程序：
@Provider
public class EntityNotFoundMapper implements ExceptionMapper<CustomNotFoundException> {
public Response toResponse(CustomNotFoundException ex) {
return Response.status(404).
entity("Ouchhh, this item leads to following error:" + ex.getMessage()).
type("text/plain").
build();
}
}最后，您必须注册异常映射器，以便可以在应用程序中使用它。下面是一些伪代码：
register(new EntityNotFoundMapper());
//or
register(EntityNotFoundMapper.class);页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/38971609
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