blocks|key|3175653|text|美丽胜于丑陋。|type|blockquote|depth|inlineStyleRanges|entityRanges|data|3175654|def+sum_array(arr):
++++if+arr+is+None+or+len(arr)+<=+1:
+++++++++return+0
++++else:
+++++++++return+sum(sorted(arr)[1:-1])|code-block|syntax|javascript|3175655|unstyled|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|K|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|H|7|L|8|@]|9|@]|A|$]]]|I|$]]

<blockquote>
 Beautiful is better than ugly.
</blockquote>

<pre><code>def sum_array(arr):
 if arr is None or len(arr) &lt;= 1:
 return 0
 else:
 return sum(sorted(arr)[1:-1])
</code></pre>

blocks|key|3175586|text|不知道为什么需要for中的sum。看来x在任何地方都没有使用。这可以简化为：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3175587|def+sum_array(arr):
++++return+0+if+not+arr+else+sum(sorted(arr)[1:-1])|code-block|syntax|javascript|3175588|entityMap^0|8|3|D|3|J|1|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|U|8|@]|D|@]|E|$]]]|L|$]]

Not sure why you need the <code>for</code> in the <code>sum</code>. It appears that <code>x</code> isn't used anywhere. This could be simplified to:

<pre><code>def sum_array(arr):
 return 0 if not arr else sum(sorted(arr)[1:-1])
</code></pre>

blocks|key|1647475|text|知道最大值和最小值的最简单的方法是对列表进行排序。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1647476|arr+=+sorted(arr)|code-block|syntax|javascript|1647477|arr是最小的，arr-1是最大的|1647478|所以|1647479|if+arr+is+None:
++++return+0
else:
++++return+sum(sorted(arr)[1:-1])|1647480|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|S|8|@]|9|@]|A|$E|F]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

The easiest way to know where both the max and min is is to sort the list.

<pre><code>arr = sorted(arr)
</code></pre>

arr[0] is the smallest, arr[-1] is the largest

So

<pre><code>if arr is None:
 return 0
else:
 return sum(sorted(arr)[1:-1])
</code></pre>

blocks|key|3175665|text|以下是满足您要求的版本：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3175666|def+sum_array(arr):
++++return+(None+if+len(arr)+<=+1+else+0)+if+not+arr+else+sum(sorted(arr)[1:-1])

cases+=+[[j+%2B+1+for+j+in+range(i)]+for+i+in+range(5)]

for+c+in+cases:
++++print(c,+sum_array(c))

#+Requirements:+Objective+is+to+calculate+sum+of+integers+minus+the+min+and
#+max.+If+array+is+empty,+None,+or+if+only+1+element+exists,+the+function
#+should+return+0.
#+[]+None
#+[1]+0
#+[1,+2]+0
#+[1,+2,+3]+2
#+[1,+2,+3,+4]+5|code-block|syntax|javascript|3175667|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here's a version which meets your requirements:

<pre><code>def sum_array(arr):
 return (None if len(arr) &lt;= 1 else 0) if not arr else sum(sorted(arr)[1:-1])

cases = [[j + 1 for j in range(i)] for i in range(5)]

for c in cases:
 print(c, sum_array(c))

# Requirements: Objective is to calculate sum of integers minus the min and
# max. If array is empty, None, or if only 1 element exists, the function
# should return 0.
# [] None
# [1] 0
# [1, 2] 0
# [1, 2, 3] 2
# [1, 2, 3, 4] 5
</code></pre>

blocks|key|3175706|text|您获得TypeError是因为您尝试使用sum列表。让我稍微修改一下您的代码：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3175707|+In[1]:+arr+=+[1,+2,+3,+4,+5]
++++++++[sorted(arr)[1:-1]+for+x+in+range(len(arr))]

Out[1]:+[[2,+3,+4],+[2,+3,+4],+[2,+3,+4],+[2,+3,+4],+[2,+3,+4]]|code-block|syntax|javascript|3175708|我改变你在列表理解上的生成器表达式来显示这个想法。实际上，您可以在每个隐式next调用上生成一个列表。这一错误的另一个后果是：|3175709|+In[2]:+sum([[1],[2],[3]])+++++++#+will+raise+TypeError
Out[2]:+TypeError:+unsupported+operand+type(s)+for+%2B:+'int'+and+'list'

+In[3]:+sum([[1],[2],[3]],+[])+++#+if+you+specify+start,+it+will+work
Out[3]:+[1,+2,+3]|3175710|sum函数的特征是sum(iterable[,+start])。和、开始和可从左到右迭代的项，并返回总计。start默认为0。迭代器的项通常是数字，并且不允许开始值是字符串。在第一种情况下，您确实试图对[1]+%2B+[2]+%2B+[3]+%2B+0进行求和，而且由于没有定义list和int之间的%2B，这就是获得TypeError的原因。在第二种情况下，[1]+%2B+[2]+%2B+[3]+%2B+[]这个操作连接列表，并且是完全有效的。|3175711|如果您希望查看代码和一些反馈，请查看Stackexchange的CodeReview站点。|3175712|你可以试试这个，如果你喜欢单线的话。这里还假设一个有效的数组总是<class+list>的实例|3175713|+In[4]:+sum_array+=+lambda+arr:+sum(sorted(arr)[1:-1])+if+isinstance(arr,+list)+else+0
++++++++sum_array([4,+3,+8,+1,+7,+12,+5,+9])
Out[4]:+36|3175714|，但这不是很好的练习！|BOLD|3175715|entityMap|0|LINK|mutability|MUTABLE|url|https://codereview.stackexchange.com/^0|3|9|K|3|0|0|11|4|0|0|0|3|9|M|1H|5|2T|J|3P|4|3U|3|40|1|4S|K|0|W|A|0|0|W|C|0|0|0|B|0^^$0|@$1|2|3|4|5|6|7|17|8|@$9|18|A|19|B|C]|$9|1A|A|1B|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|1C|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1D|8|@$9|1E|A|1F|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|1G|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|1H|8|@$9|1I|A|1J|B|C]|$9|1K|A|1L|B|C]|$9|1M|A|1N|B|C]|$9|1O|A|1P|B|C]|$9|1Q|A|1R|B|C]|$9|1S|A|1T|B|C]|$9|1U|A|1V|B|C]|$9|1W|A|1X|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|6|7|1Y|8|@]|D|@$9|1Z|A|20|1|21]]|E|$]]|$1|S|3|T|5|6|7|22|8|@$9|23|A|24|B|C]]|D|@]|E|$]]|$1|U|3|V|5|H|7|25|8|@]|D|@]|E|$I|J]]|$1|W|3|X|5|6|7|26|8|@$9|27|A|28|B|Y]]|D|@]|E|$]]|$1|Z|3|-4|5|6|7|29|8|@]|D|@]|E|$]]]|10|$11|$5|12|13|14|E|$15|16]]]]

You get <code>TypeError</code> because you try to <code>sum</code> lists. Let me change your code a little bit:

<pre><code> In[1]: arr = [1, 2, 3, 4, 5]
 [sorted(arr)[1:-1] for x in range(len(arr))]

Out[1]: [[2, 3, 4], [2, 3, 4], [2, 3, 4], [2, 3, 4], [2, 3, 4]]
</code></pre>

I change your generator expression on list comprehension to show the idea. Really you generate a list on each implicit <code>next</code> call. A further consequence of this error is:

<pre><code> In[2]: sum([[1],[2],[3]]) # will raise TypeError
Out[2]: TypeError: unsupported operand type(s) for +: 'int' and 'list'

 In[3]: sum([[1],[2],[3]], []) # if you specify start, it will work
Out[3]: [1, 2, 3]
</code></pre>

The signature of <code>sum</code> function is <code>sum(iterable[, start])</code>. Sums start and the items of an iterable from left to right and returns the total. <code>start</code> defaults to 0. The iterable‘s items are normally numbers, and the start value is not allowed to be a string. In fist case you really try to sum <code>[1] + [2] + [3] + 0</code>, and because <code>+</code> between <code>list</code> and <code>int</code> is not defined, that's why you get TypeError. In the second case <code>[1] + [2] + [3] + []</code> this operation concatenates list and is perfectly valid.

And if you want review of your code and some feedback look at Stackexchange's <a href="https://codereview.stackexchange.com/">CodeReview</a> site.

You can try this, if you like one-liners. Here is also an assumption that a valid array is always instance of <code>&lt;class list&gt;</code>:

<pre><code> In[4]: sum_array = lambda arr: sum(sorted(arr)[1:-1]) if isinstance(arr, list) else 0
 sum_array([4, 3, 8, 1, 7, 12, 5, 9])
Out[4]: 36
</code></pre>

But it's not good practice!

Trying to practice my list comprehension, but at this point my code is looking a little (too) long per line length comprehension: 

<pre><code>def sum_array(arr):
 return 0 if arr == None else sum(sorted(arr)[1:-1] for x in range(len(arr or [])-2)) 
</code></pre>

Objective is to calculate sum of integers minus the min and max. If array is empty, <code>None</code>, or if only 1 element exists, the function should return 0.

I am receivingthe following

<blockquote>
 TypeError: unsupported operand type(s) for +: 'int' and 'list'
</blockquote>

Please advise!

Sum of list without lowest and highest list integers (python)

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尝试练习我的列表理解，但此时我的代码看起来有点(太长)每一行长度理解：def sum_array(arr):    return 0 if arr == None else sum(sorted(arr)[1:-1] for x in range(len(arr or [])-2)) 目标是计算整数之和减去最小和最大值。如果数组是空的，None，或者如果只有一个元素，则函数应该返回0。我收到以下消

问没有最低和最高列表整数的列表之和(python)
EN

回答 5

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问没有最低和最高列表整数的列表之和(python)
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