我正在用令牌在c#中做一个web,但是我需要将postman的参数接收到我的方法
[HttpPost, Route("api/cobro/saveEmail")]
public IHttpActionResult SaveEmailForDiscount([FromBody] string email)
{
//do something with e-mail
return Ok(email);
}
但电子邮件总是为空
这是PostMan请求
POST /api/cobro/saveEmail HTTP/1.1
Host: localhost:53107
Content-Type: application/x-www-form-urlencoded
Cache-Control: no-cache
Postman-Token: 881045b2-0f08-56ac-d345-ffe2f8f87f5e
email=jose%40gm.com
这是我的启动类,其中所有的配置
using System;
using Microsoft.Owin;
using Owin;
using Microsoft.Owin.Security.OAuth;
using System.Web.Http;
using System.Net.Http.Headers;
[assembly: OwinStartup(typeof(Cobros_BackEnd.Startup))]
namespace Cobros_BackEnd
{
public class Startup
{
public void Configuration(IAppBuilder app)
{
app.UseCors(Microsoft.Owin.Cors.CorsOptions.AllowAll);
var MyProvider = new AuthorizationServerProvider();
OAuthAuthorizationServerOptions options = new OAuthAuthorizationServerOptions
{
AllowInsecureHttp = true,
TokenEndpointPath = new PathString("/token"),
AccessTokenExpireTimeSpan = TimeSpan.FromDays(1),
Provider = MyProvider
};
app.UseOAuthAuthorizationServer(options);
app.UseOAuthBearerAuthentication(new OAuthBearerAuthenticationOptions());
HttpConfiguration config = new HttpConfiguration();
config.Formatters.JsonFormatter.SupportedMediaTypes
.Add(new MediaTypeHeaderValue("text/xml"));
//get all users
config.Routes.MapHttpRoute(
name: "Users",
routeTemplate: "api/{controller}/users",
defaults: new { id = RouteParameter.Optional }
);
WebApiConfig.Register(config);
}
}
}
我在GET中使用其他方法,一切都很好,但是我需要在POST上使用这个
发布于 2017-03-17 20:55:20
可以创建一个类包装电子邮件字段,如下所示
public class SaveEmailModel{
public string Email{get;set;}
}
public IHttpActionResult SaveEmailForDiscount([FromBody] SaveEmailModel model){
...
}
发布于 2017-03-17 20:27:08
在您的请求正文中尝试以下内容:=jose%40gm.com
Web对在帖子正文中传递的简单类型不友好。您需要实际实现一个自定义数据绑定器才能做到这一点。我刚才说的是一件工作。我避免在body中发布简单类型,而在Web中不惜一切代价。Id更喜欢创建一个model对象,然后用JSON发送数据,这将映射到我的模型。您还可以使用FromUri并将字符串传递到url中。
https://stackoverflow.com/questions/42866443
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