如果jquery对象具有许多级别的后代,那么如何排除某些后代及其后代呢?假设在要排除的元素的顶部节点上有一个类(在本例中是.foo
),并且您的jquery对象是下面的div1
。
编辑:澄清:我想排除所有.foo
的后代,而不仅仅是直接的孩子。
$('#button1').click(function() {
var selector = '#test ' + $('#input1').val();
var numberElements = $(selector).length;
$('#numberElements').text(numberElements);
var elementsAsCommaSeparatedList = _.pluck($(selector), 'id');
$('#elementList').text(elementsAsCommaSeparatedList.join(', '));
});
#input1 {
width: 230px;
font-size: 16px;
font-weight: bold;
}
#numberElements,
#elementList {
color: green;
font-weight: bold;
font-size: 20px;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.8.3/underscore-min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<label for="input1">Please supply a selector... $('<input id="input1" value="div:not(.foo, .foo *)"></label>')
<button id="button1">Apply Selector</button>
<div>(default value is from @DaniP's answer)</div>
<div id="result"><span>Number of elements selected: </span><span id="numberElements">0</span></div>
<div>
<span>Elements selected (by id):</span>
<span id="elementList"></span>
</div>
<div id="test">
<div id="div1">
<div id="div2">
<div id="div4">
<div id="div8"></div>
<div id="div9"></div>
</div>
<div id="div5" class="foo">
<div id="div10"></div>
<div id="div11"></div>
</div>
</div>
<div id="div3">
<div id="div6">
<div id="div12"></div>
<div id="div13"></div>
</div>
<div id="div7" class="foo">
<div id="div14"></div>
<div id="div15"></div>
</div>
</div>
</div>
</div>
发布于 2017-03-24 20:25:29
也许使用:而不是选择器?
有点像
div:not(.foo)
https://stackoverflow.com/questions/43008463
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