这是一个有趣的问题:我正在尝试测试一个使用Ionic BarcodeScanner的服务。为了尝试测试,我有一个基于离子单元-测试库的回购。我正在通过BarcodeScanner.scan模拟spyOn(..).and.callFake(..)
方法
问题:当我从组件调用扫描方法时,它会工作。当我在服务中做完全相同的事情时,它会抛出一个超时。
组件测试代码:
it("should be able to set a spy on the scanner and test the component", done => {
const testBC = "123456";
const spy = spyOn(TestBed.get(BarcodeScanner), "scan");
spy.and.callFake(() => {
return new Promise((resolve, reject) => {
resolve(testBC);
})
});
component.testScanner().then(res => {
expect(res).toBe(testBC);
done();
}, reason => {
expect(true).toBe(false);
done();
})
});
服务测试代码:
it("should be able to set a spy on the scanner and test the service", done => {
const testBC = "123456";
const spy = spyOn(TestBed.get(BarcodeScanner), "scan");
spy.and.callFake(() => {
return new Promise((resolve, reject) => {
resolve(testBC);
})
});
inject([TestService], (service) => {
service.testScanner().then(res => {
expect(res).not.toBe(testBC);
done()
}, reason => {
expect(true).toBe(false);
done();
})
})
});
有任何已知的问题,测试服务的角度2的方式吗?任何帮助都很感激!
发布于 2017-12-10 23:29:04
问题是不调用注入函数。
服务的测试代码现在如下所示:
it("should be able to set a spy on the scanner and test the service", done => {
const testBC = "123456";
const spy = spyOn(TestBed.get(BarcodeScanner), "scan");
spy.and.callFake(() => {
return new Promise((resolve, reject) => {
resolve(testBC);
})
});
inject([TestService], (service) => {
service.testScanner().then(res => {
expect(res).not.toBe(testBC);
done()
}, reason => {
expect(true).toBe(false);
done();
})
})(); //<-- do not forget these braces!!
});
https://stackoverflow.com/questions/47632138
复制相似问题