问Selenium:元素当前不可见，因此可能无法交互
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Stack Overflow用户

提问于 2016-09-19 21:09:29

回答 1查看 679关注 0票数 0

我正在尝试创建一个自动登录netflix网站的脚本：https://www.netflix.com/it/

这就是代码：

from selenium import webdriver
from selenium.webdriver.common.keys import Keys

driver = webdriver.Firefox()
while True:
    driver.get("https://www.netflix.com/it/")
    login = driver.find_element_by_css_selector(".authLinks.signupBasicHeader")
    login.click()
    element = driver.find_element_by_name("email")
    element.send_keys("test1@email.com")
    submit = driver.find_element_by_css_selector(".btn.login-button.btn-submit.btn-small")
    submit.click()
    element2 = driver.find_element_by_name("password")
    element2.send_keys("test1")
    submit.click()

但它有时起作用，有时不起作用，并引发此异常：

Traceback (most recent call last):
  File "netflix.py", line 35, in <module>
    submit.click()
  File "/home/user/.local/lib/python3.5/site-packages/selenium/webdriver/remote/webelement.py", line 72, in click
    self._execute(Command.CLICK_ELEMENT)
  File "/home/user/.local/lib/python3.5/site-packages/selenium/webdriver/remote/webelement.py", line 461, in _execute
    return self._parent.execute(command, params)
  File "/home/user/.local/lib/python3.5/site-packages/selenium/webdriver/remote/webdriver.py", line 236, in execute
    self.error_handler.check_response(response)
  File "/home/user/.local/lib/python3.5/site-packages/selenium/webdriver/remote/errorhandler.py", line 192, in check_response
    raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.ElementNotVisibleException: Message: Element is not currently visible and so may not be interacted with
Stacktrace:
    at fxdriver.preconditions.visible (file:///tmp/tmp7otgskq8/extensions/fxdriver@googlecode.com/components/command-processor.js:10092)
    at DelayedCommand.prototype.checkPreconditions_ (file:///tmp/tmp7otgskq8/extensions/fxdriver@googlecode.com/components/command-processor.js:12644)
    at DelayedCommand.prototype.executeInternal_/h (file:///tmp/tmp7otgskq8/extensions/fxdriver@googlecode.com/components/command-processor.js:12661)
    at DelayedCommand.prototype.executeInternal_ (file:///tmp/tmp7otgskq8/extensions/fxdriver@googlecode.com/components/command-processor.js:12666)
    at DelayedCommand.prototype.execute/< (file:///tmp/tmp7otgskq8/extensions/fxdriver@googlecode.com/components/command-processor.js:12608)

异常说明web页面的一部分是不可见的(即使该部分实际上在页面中)……这是一种bug。我怎么才能绕过它呢？

python

python-3.x

selenium

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回答 1

Stack Overflow用户

发布于 2016-09-19 22:01:41

不需要将测试代码放入while循环中，因为登录表单应该提交一次。我猜当它成功工作时，下一次迭代会产生错误，因为没有表单。

您还可以在输入密码之前和之后单击submit按钮。最好是在表单填满后单击，如果可能，不要测试空表单。

from selenium import webdriver

driver = webdriver.Firefox()
driver.get("https://www.netflix.com/it/")
login = driver.find_element_by_css_selector(".authLinks.signupBasicHeader")
login.click()
element = driver.find_element_by_name("email")
element.send_keys("test1@email.com")
submit = driver.find_element_by_css_selector(".btn.login-button.btn-submit.btn-small")
submit.click()
element2 = driver.find_element_by_name("password")
element2.send_keys("test1")
submit = driver.find_element_by_css_selector(".btn.login-button.btn-submit.btn-small")
submit.click()