问Python:从阶乘(N)中获取最后一个非零元素

EN

a = str(factorial)
output = int(a.replace('0', '')[-1])

def fact(n):
    if n==0:
            return 1
    else :
            return n*fact(n-1)


x = fact(44)    # x =2658271574788448768043625811014615890319638528000000000L
y=str(x)[::-1] # convert x to string and invers it
str(int(y))[0]  # convert y to int after to string and get the first char 
#8

from functools import reduce

def fact(n):
    if n==0:
        return 1
    else :
        # in python 2 replace range by xrange:
        return reduce(lambda x, y: x * y, range(1, n+1))

def last_non_zero(n):
    while n:
        d = n%10
        if d!=0:
            return d
        else:
            n //= 10

N = 1000
f = fact(N)
print("factorial of {} is : {}".format(N, f))
print("last non zero is:", last_non_zero(f))