我正在尝试通过与django ORM进行连接来获取数据。但是有一个问题,如下所示。
django中的模型:
class LawyerCounsel(models.Model):
lawyer_idx = models.AutoField(primary_key=True)
lawyer_name = models.CharField(max_length=50)
lawyer_status = models.CharField(max_length=1)
register_date = models.DateTimeField()
lawyeridx = models.ForeignKey(CounselAnswer, to_field='lawyer_idx',
unique='true', db_column="counsel_answer_idx", on_delete="models.DO_NOTHING")
class Meta:
managed = False
db_table = 'lawyer'
class CounselAnswer(models.Model):
counsel_answer_idx = models.AutoField(primary_key=True)
counsel_idx = models.IntegerField()
lawyer_idx = models.IntegerField()
counsel_answer_title = models.CharField(max_length=255)
counsel_answer_contents = models.TextField()
counsel_seleted = models.CharField(max_length=1)
counsel_answer_agree = models.IntegerField()
lawyer_ip = models.CharField(max_length=20, blank=True, null=True)
counsel_answer_delay_time = models.IntegerField()
register_date = models.DateTimeField()
update_date = models.DateTimeField()
class Meta:
managed = False
db_table = 'counsel_answer'
我需要从数据库中选择
stats_data_test = LawyerCounsel.objects.filter(register_date=yearmonth).order_by("cnt")
我可以使用django ORM进行此选择吗?(例如,在SQL中,select如下所示)
select * from (
select
y.lawyer_name,
DATE_FORMAT(y.register_date, '%Y-%m-%d') as reg_date,
(select count(counsel_answer_idx) from counsel_answer where lawyer_idx = y.lawyer_idx and DATE_FORMAT(register_date, "%Y%m") = '201903') as cnt,
(select count(counsel_answer_idx) from counsel_answer where lawyer_idx = y.lawyer_idx and DATE_FORMAT(register_date, "%Y%m") = '201903' and week(register_date,5) - week(DATE_SUB(register_date,INTERVAL DAYOFMONTH(register_date)-1 DAY),5) = 1) as cnt1,
(select count(counsel_answer_idx) from counsel_answer where lawyer_idx = y.lawyer_idx and DATE_FORMAT(register_date, "%Y%m") = '201903' and week(register_date,5) - week(DATE_SUB(register_date,INTERVAL DAYOFMONTH(register_date)-1 DAY),5) = 2) as cnt2,
(select count(counsel_answer_idx) from counsel_answer where lawyer_idx = y.lawyer_idx and DATE_FORMAT(register_date, "%Y%m") = '201903' and week(register_date,5) - week(DATE_SUB(register_date,INTERVAL DAYOFMONTH(register_date)-1 DAY),5) = 3) as cnt3,
(select count(counsel_answer_idx) from counsel_answer where lawyer_idx = y.lawyer_idx and DATE_FORMAT(register_date, "%Y%m") = '201903' and week(register_date,5) - week(DATE_SUB(register_date,INTERVAL DAYOFMONTH(register_date)-1 DAY),5) = 4) as cnt4,
(select count(counsel_answer_idx) from counsel_answer where lawyer_idx = y.lawyer_idx and DATE_FORMAT(register_date, "%Y%m") = '201903' and week(register_date,5) - week(DATE_SUB(register_date,INTERVAL DAYOFMONTH(register_date)-1 DAY),5) = 5) as cnt5,
(select count(counsel_answer_idx) from counsel_answer where lawyer_idx = y.lawyer_idx and DATE_FORMAT(register_date, "%Y%m") = '201903' and week(register_date,5) - week(DATE_SUB(register_date,INTERVAL DAYOFMONTH(register_date)-1 DAY),5) = 6) as cnt6
from lawyer y
where y.lawyer_status = 'N'
) A order by A.cnt desc;
发布于 2019-03-22 14:51:24
是的,你可以做到这一点。您需要使用Django QuerySet .annotate
功能将这些select子查询注释到您的模型上。
在将该值注释到QuerySet上之后,.order_by
就可以访问它了。
https://stackoverflow.com/questions/55291710
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