问有没有一个简单的正则表达式来检查日期格式模式？

EN

const regex = /(\d{1,2}(?:-|\/)\d{1,2}(?:-|\/)(?:\d{4}|\d{2}))|(\d{4}\.\d{1,2}\.\d{1,2})/gm

// valid cases
regex.test('1-01-2000')
regex.test('12-1-2000')
regex.test('10/10/11')
regex.test('10/1/2011')
regex.test('1/1/2011')
regex.test('2000.12.1')
regex.test('2000.1.11')

const test = (str) => {
  // Check main pattern
  const m = str.match(/^([md]{1,2}|y{4}|y{2})[-\/\.]([md]{1,2}|y{4}|y{2})[-\/\.]([md]{1,2}|y{4}|y{2})$/i);
  
  // Print false
  const noMatch = () => console.log('Not match!', str);
  
  // If no matched groups
  if(!m) {
    noMatch();
    return false;
  }
  // Unique obj
  const unique = {};
  
  // Check if all match is unique
  const mArr = ["d", "m", "y"];
  for(let i = 1; i < m.length; i++) {
    const mStr = m[i];
    // Loop avaliable char
    for(let i = 0; i < mArr.length; i++) {
      const re = new RegExp(`^[${mArr[i]}]+$`, "i");
      // If match char
      if(re.test(mStr)) {
        // If already in unique object
        if(unique[mArr[i]]) {
          noMatch();
          return false;
        } else unique[mArr[i]] = true;
      }
    }
  }
  
  // Match
  console.log('Matched!', str);
}

test('dd-mm-yyyy');
test('YYYY/MM/DD');
test('dd.mm.yy');
test('dd.dd.yyyy');
test('dd|mm|yyyy');
test('ddd-mmm-yyyy');
test('dd/mm/yyy');