一种高效替换Python字符串串中错误单词的方法

text = "This is a smaple text with some erors."
corrected_text = text.replace("smaple", "sample").replace("erors", "errors")
print(corrected_text)

import re

text = "This is a smaple text with some erors."
pattern = re.compile(r'\bsmaple\b|\berors\b')
corrected_text = pattern.sub(lambda x: "sample" if x.group() == "smaple" else "errors", text)
print(corrected_text)

import re

text = "This is a smaple text with some erors and smaple erors."

# 错误单词和正确单词的映射
corrections = {
    "smaple": "sample",
    "erors": "errors"
}

# 构建正则表达式模式
pattern = re.compile(r'\b(' + '|'.join(re.escape(key) for key in corrections.keys()) + r')\b')

# 替换函数
def replace(match):
    return corrections[match.group(0)]

# 执行替换
corrected_text = pattern.sub(replace, text)
print(corrected_text)