两个函数的Python交点

def f1(x):
    return x**2

def f2(x):
    return 2*x - 1

def find_intersection():
    threshold = 0.001
    x = 0
    while abs(f1(x) - f2(x)) > threshold:
        x += 0.001
    y = f1(x)
    return x, y

intersection = find_intersection()
print("交点坐标：", intersection)

import matplotlib.pyplot as plt
import numpy as np

def f1(x):
    return x**2

def f2(x):
    return 2*x - 1

x = np.linspace(-10, 10, 100)
y1 = f1(x)
y2 = f2(x)

plt.plot(x, y1, label='f1(x) = x^2')
plt.plot(x, y2, label='f2(x) = 2x-1')
plt.xlabel('x')
plt.ylabel('y')
plt.legend()
plt.grid(True)

# 标注交点
intersection_x = 0.5
intersection_y = f1(intersection_x)
plt.scatter(intersection_x, intersection_y, color='red', label='Intersection')
plt.annotate(f'({intersection_x}, {intersection_y})', (intersection_x, intersection_y), textcoords="offset points", xytext=(-10,-10), ha='center')

plt.show()