两个大型2d列表之间的python快速均方误差

import numpy as np

def calculate_mse(list1, list2):
    array1 = np.array(list1)
    array2 = np.array(list2)
    mse = np.mean((array1 - array2) ** 2)
    return mse

list1 = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
list2 = [[2, 3, 4], [5, 6, 7], [8, 9, 10]]

mse = calculate_mse(list1, list2)
print("均方误差：", mse)

均方误差： 2.6666666666666665