为Groovy中XML文件中的每一行返回XPath

import groovy.util.XmlSlurper
import groovy.util.slurpersupport.NodeChild

def xml = new XmlSlurper().parse(new File("path/to/xml/file.xml"))

def getXPath(node) {
    def path = ""
    while (node.parent() instanceof NodeChild) {
        def index = node.parent().children().indexOf(node)
        path = "/${node.name()}[$index]" + path
        node = node.parent()
    }
    return path
}

xml.depthFirst().each { node ->
    println getXPath(node)
}