从列表中生成2*2元组并在python中查找重复的元组

lst = [1, 2, 3, 4, 1, 2, 3, 4, 5, 6]

tuples = [(lst[i], lst[i+1]) for i in range(0, len(lst), 2)]

[(1, 2), (3, 4), (1, 2), (3, 4), (5, 6)]

duplicate_tuples = set([t for t in tuples if tuples.count(t) > 1])

print(duplicate_tuples)

lst = [1, 2, 3, 4, 1, 2, 3, 4, 5, 6]
tuples = [(lst[i], lst[i+1]) for i in range(0, len(lst), 2)]
duplicate_tuples = set([t for t in tuples if tuples.count(t) > 1])
print(duplicate_tuples)

{(1, 2), (3, 4)}