从字符串中检索持续时间(秒)

import re

def retrieve_duration_seconds(string):
    # 使用正则表达式匹配出时间信息
    pattern = r'(\d+)\s*(seconds?|secs?|s)|(\d+)\s*(minutes?|mins?|m)|(\d+)\s*(hours?|hrs?|h)|(\d+)\s*(days?|d)'
    matches = re.findall(pattern, string)

    # 将时间信息转换为秒数
    total_seconds = 0
    for match in matches:
        if match[1] in ['second', 'seconds', 'sec', 'secs', 's']:
            total_seconds += int(match[0])
        elif match[3] in ['minute', 'minutes', 'min', 'mins', 'm']:
            total_seconds += int(match[2]) * 60
        elif match[5] in ['hour', 'hours', 'hr', 'hrs', 'h']:
            total_seconds += int(match[4]) * 3600
        elif match[7] in ['day', 'days', 'd']:
            total_seconds += int(match[6]) * 86400

    return total_seconds

# 示例用法
string = "The duration is 2 hours and 30 minutes."
duration_seconds = retrieve_duration_seconds(string)
print("Duration in seconds:", duration_seconds)