从2D数组的左下角开始获取具有2D坐标的1D项

[                    [
 [1, 2, 3, 4],        [1, 2, 3, 4],
 [5, 6, 7, 8],   =>   [5, 6, 7, 8],
 [9, 10, 11, 12]       [9,10,11,12]
]                    ]

def get_1D_item_from_2D_array(array, x, y):
    row = len(array) - 1  # 最后一行的索引
    col = 0  # 第一列的索引

    while row >= 0 and col < len(array[0]):
        if array[row][col][0] == x and array[row][col][1] == y:
            return array[row][col]
        elif array[row][col][0] > x:
            row -= 1
        else:
            col += 1

    return None  # 没有找到对应的1D项

# 用法示例
array = [
    [[0, 0], [0, 1], [0, 2], [0, 3]],
    [[1, 0], [1, 1], [1, 2], [1, 3]],
    [[2, 0], [2, 1], [2, 2], [2, 3]],
]
x = 1
y = 2
result = get_1D_item_from_2D_array(array, x, y)
print(result)  # 输出：[1, 2]