从JSON对象c#构建属性列表

using Newtonsoft.Json;

string json = "{\"name\":\"John\", \"age\":30, \"city\":\"New York\"}";

dynamic obj = JsonConvert.DeserializeObject(json);

string name = obj.name;
int age = obj.age;
string city = obj.city;

public class Person
{
    public string Name { get; set; }
    public int Age { get; set; }
    public string City { get; set; }
}

string json = "{\"name\":\"John\", \"age\":30, \"city\":\"New York\"}";

Person person = JsonConvert.DeserializeObject<Person>(json);

string name = person.Name;
int age = person.Age;
string city = person.City;