从SQLAlchemy查询的`filter_by`选项中删除kwargs的最佳方法

from sqlalchemy import create_engine, Column, Integer, String
from sqlalchemy.orm import sessionmaker
from sqlalchemy.ext.declarative import declarative_base

# 创建数据库连接
engine = create_engine('mysql+pymysql://username:password@localhost:3306/database')
Session = sessionmaker(bind=engine)
session = Session()

# 定义模型
Base = declarative_base()

class User(Base):
    __tablename__ = 'users'
    id = Column(Integer, primary_key=True)
    name = Column(String(50))
    age = Column(Integer)

# 查询年龄大于等于18的用户
users = session.query(User).filter(User.age >= 18).all()

# 查询名字为"John"且年龄大于等于18的用户
users = session.query(User).filter(User.name == "John", User.age >= 18).all()