以两个字节查找公共前缀的长度

def find_common_prefix_length(byte1, byte2):
    binary1 = bin(byte1)[2:].zfill(8)  # 将字节转换为8位二进制形式
    binary2 = bin(byte2)[2:].zfill(8)
    
    length = 0
    for i in range(8):
        if binary1[i] == binary2[i]:
            length += 1
        else:
            break
    
    return length

byte1 = 0b11011010  # 示例字节1
byte2 = 0b11011111  # 示例字节2
prefix_length = find_common_prefix_length(byte1, byte2)
print("公共前缀的长度为:", prefix_length)