使用period列迭代date列，直至结束日期；按id列对结果进行分组。

# 假设数据存储在一个名为data的列表中，每个元素包含id、period和date字段
data = [
    {"id": 1, "period": {"start": "2022-01-01", "end": "2022-01-05"}, "date": "2022-01-01"},
    {"id": 1, "period": {"start": "2022-01-01", "end": "2022-01-05"}, "date": "2022-01-02"},
    {"id": 1, "period": {"start": "2022-01-01", "end": "2022-01-05"}, "date": "2022-01-03"},
    {"id": 1, "period": {"start": "2022-01-01", "end": "2022-01-05"}, "date": "2022-01-04"},
    {"id": 1, "period": {"start": "2022-01-01", "end": "2022-01-05"}, "date": "2022-01-05"},
    {"id": 2, "period": {"start": "2022-02-01", "end": "2022-02-03"}, "date": "2022-02-01"},
    {"id": 2, "period": {"start": "2022-02-01", "end": "2022-02-03"}, "date": "2022-02-02"},
    {"id": 2, "period": {"start": "2022-02-01", "end": "2022-02-03"}, "date": "2022-02-03"},
]

# 创建一个字典用于存储分组结果
result = {}

# 遍历数据列表
for item in data:
    # 获取当前数据的id和period信息
    id = item["id"]
    period = item["period"]
    
    # 获取当前period的开始日期和结束日期
    start_date = period["start"]
    end_date = period["end"]
    
    # 获取当前数据的date信息
    date = item["date"]
    
    # 判断当前date是否在period的时间范围内
    if start_date <= date <= end_date:
        # 如果当前id不存在于结果字典中，则创建一个空列表作为值
        if id not in result:
            result[id] = []
        
        # 将当前date添加到对应id的列表中
        result[id].append(date)

# 输出结果
for id, dates in result.items():
    print("id:", id)
    print("dates:", dates)
    print("------")