使用python生成特定范围的十六进制数

def generate_hex_numbers(start, end):
    hex_numbers = []
    for i in range(start, end + 1):
        hex_numbers.append(hex(i))
    return hex_numbers

# 示例：生成从10到20的十六进制数
start = 10
end = 20
hex_numbers = generate_hex_numbers(start, end)
print(hex_numbers)

['0xa', '0xb', '0xc', '0xd', '0xe', '0xf', '0x10', '0x11', '0x12', '0x13', '0x14']

# 错误示例
start = 10
end = 20
hex_numbers = [hex(i) for i in range(start, end)]  # 这里少加了1
print(hex_numbers)  # 会少一个数

# 正确示例
hex_numbers = [hex(i) for i in range(start, end + 1)]
print(hex_numbers)

hex_numbers = [hex(i)[2:] for i in range(start, end + 1)]
print(hex_numbers)